of banana oil‚ once synthesized it will be purified by distillation. Then the analysis of the sample using H NMR and IR will determine purity of the product. Reaction Scheme: Mechanism: Fischer esterification is the acid catalyzed condensation of an alcohol and a carboxylic acid‚ where it is protonated at the carbonyl oxygen‚ then the nucleophillic attack of the alcohol. The proton
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reaction of 1-propanol and 2-pentanol with NaBr in H2SO4‚ in which the H2O acts as the leaving group and Br as the attaching nucleophile (1). After the reaction has taken place through reflux and distillation‚ the product is able to be examined through NMR and IR spectroscopy analysis. Finally‚ these graphs will help in determining the products of each reaction and the type of mechanism used. SN1: SN2: Mechanism of 1-propanol: Mechanism of 2-pentanol: Table of Reagents Compound | Molecular
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an ice bath until crystallization occurs 8. Filter the crude product 9. Recrystallize with 2 mL of EtOH 10. Filter pure product and collect MP and mass 11. Perform a saturation test with a bromine and potassium permanganate solution 12. Obtain NMR from instructor and identify peaks Apparatus: Post Lab: Observations:
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the IR spectra‚ the NMR of the unknown was analyzed. First‚ the general region was predicted to give an idea of how the molecular may look like. Based on the chart‚ it does seem like a ketone was present with a couple of C-H stretches near the functional group. Next‚ four H proton signals and five carbons singles were identified on both of the H and C NMR. Finally‚ the splitting pattern was identified where it provided where the C-H bonds were potentially located on the H NMR . With the molecular
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amine group. NMR is a technique that measures both the molecular structure and the purity of the compound4. It does so by taking advantage of the polarity of the molecules4. NMR applies an external magnet to the molecule and‚ based on the change in energy of the protons‚ identifies if they are equivalent protons or not4. The larger the peak on the resulting graph‚ the larger the number of equivalent protons. If the peaks have splitting in them‚ it indicates that there are protons on a nearby atom
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Bromination of Acetanilide Objective: The objective of this experiment was to use melting point and NMR to determine which of two isomers‚ ortho or para‚ would most likely form after brominating Acetanilide through electrophilic aromatic substitution. Procedure/Observations: 1. Weigh out ~280 mg of acetanilide in a 10 mL r.b. flask with a stir bar. 2. Then‚ add 2.0 mL of glacial acetic acid using a calibrated Pasteur pipet. 3. Stir the mixture until all of the acetanilide has dissolved
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Experiment C. Aim: To protect one of two carbonyl groups (C1) in order to allow the other to react twice with a Grignard followed by removal of the protecting group by acid hydrolysis to give final product (C2). Method: Ethyl acetoacetate (30.03g)‚ ethylene glycol (15.01g) and toluene-p-sulphonic acid (0.13g) were added to a 250 cm3 round bottomed flask‚ containing a stirrer bar and toluene (100 cm3)‚ fitted with a condenser and dean-stark head. Solution was heated strongly under reflux using
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compound. The other two peaks correspond to the peaks of aromatic carbon-carbon double bonds. The proton NMR acquired indicates two different hydrogen’s present in the compound which correctly corresponds to triphenylmethanol. The peak at about 7.4ppm is the peak for the aromatic hydrogens on the three phenyl rings. The peak at about 3.6ppm is the hydrogen part of the hydroxyl group. The carbon NMR acquired also corroborates the conclusion that the final compound is triphenylmethanol. The peak
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The percentage yield was calculated to be (0.1203/2.352) *100 = 5.11%. A sample of the crystals was then taken and dissolved in around 1 ml of deuterated chloroform and the solution was transferred was transferred to an NMR tube. The NMR tube was handed to the lab TF and the NMR spectrum was received a few hours later. Post-lab Conclusions The percent yield calculated was around 5%. The percent yield of the white crystal
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Nitration of Methyl Benzoate to form Methyl-m-nitrobenzoate via Aromatic Substitution Linh Ngoc Thuy Nguyen Seattle Central Community College Professor: Dr. Esmaeel Naeemi Date: February 21st‚ 2012 Abstract In this experiment‚ methyl-m-nitrobenzoate‚ followed the electrophilic addition of aromatic ring‚ would be formed from the starting material methyl benzoate and nitric acid‚ under the catalysis of concentrated sulfuric acid. The reaction between nitric acid and sulfuric acid resulted
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