IB Biology Potato Lab
IB Biology Potato Lab
Table 1: Trial Number | Concentration of Sucrose Solution (M) ±0.2 ml | Initial Mass of Potato Core Slice(g) ±0.1 | Final Mass of Potato Core Slices (g) ±0.1 | 1 | 0.0 | 7.7 | 9.3 | 2 | | 6.0 | 8.1 | 3 | | 6.2 | 7.4 | 4 | | 10.2 | 13.2 | 5 | | 8.7 | 10.3 | 6 | | 4.9 | 6.0 | 7 | | 9.2 | 10.4 | 1 | 0.2 | 5.8 | 6.0 | 2 | | 11.6 | 12.1 | 3 | | 2.5 | 3.1 | 1 | 0.4 | 14.4 | 13.9 | 2 | | 2.6 | 2.8 | 3 | | 8 | 6.5 | 1 | 0.6 | 7.3 | 5.3 | 2 | | 10.7 | 7.3 | 3 | | 9.6 | 7.4 | 4 | | 2.9 | 2.8 | 1 | 0.8 | 5.6 | 3.6 | 2 | | 16.0 | 13.1 | 3 | | 11.5 | 5.9 | 1 | 1.0 | 7.9 | 5.4 | 2 | | 10.0 | 6.7 | 3 | | 9.6 | 6.2 | 4 | | 4.7 | 3.2 |
Table 2: Calculations of Averages Concentration of Sucrose Solution (M) ±0.2 ml | Average Initial Mass of Potato Core Slice(g) ±0.1 | Average Final Mass of Potato Core Slices (g) ±0.1 | Change in Mass (g) ±0.1 | Percentage Change in Mass (%) | Standard Deviation of Initial Mass | Standard Deviation of Final Mass | 0.0 | 7.6 | 9.2 | 1.6 | 22.3 | 1.9 | 2.4 | 0.2 | 6.6 | 7.1 | 0.5 | 6.5 | 4.6 | 4.6 | 0.4 | 8.3 | 7.7 | -0.6 | -7.2 | 5.9 | 5.7 | 0.6 | 7.6 | 5.7 | -1.9 | -25.2 | 3.5 | 2.2 | 0.8 | 11.0 | 7.5 | -3.5 | -31.7 | 5.2 | 5.0 | 1.0 | 8.1 | 5.4 | -2.7 | -33.2 | 2.4 | 1.5 |
Sample Calculations:
To find average of initial mass of potato core with 0.2M solution:
# 1 + # 2 + # 3 / 3
5.8 + 11.6 +2.5 / 3 = 6.6
To find average of final mass of potato core with 1.0M solution:
# 1 + # 2 + # 3 + # 4 / 4
5.4 + 6.7 + 6.2 + 3.2 / 4 = 5.4
To find change in mass in 0.4M solution:
Final mass – initial mass = change in mass
7.7 – 8.3 = -0.6
To find percentage change in mass in 0.6M solution:
Final – initial / initial x 100
5.7 – 7.6 / 7.6 x 100 = -25.2
Figure 1: The effect of sucrose solution on the mass of potato cores
Figure 1: In the above graph, it’s visible that with an increasing concentration of sucrose solution there is also
Table 1: Trial Number | Concentration of Sucrose Solution (M) ±0.2 ml | Initial Mass of Potato Core Slice(g) ±0.1 | Final Mass of Potato Core Slices (g) ±0.1 | 1 | 0.0 | 7.7 | 9.3 | 2 | | 6.0 | 8.1 | 3 | | 6.2 | 7.4 | 4 | | 10.2 | 13.2 | 5 | | 8.7 | 10.3 | 6 | | 4.9 | 6.0 | 7 | | 9.2 | 10.4 | 1 | 0.2 | 5.8 | 6.0 | 2 | | 11.6 | 12.1 | 3 | | 2.5 | 3.1 | 1 | 0.4 | 14.4 | 13.9 | 2 | | 2.6 | 2.8 | 3 | | 8 | 6.5 | 1 | 0.6 | 7.3 | 5.3 | 2 | | 10.7 | 7.3 | 3 | | 9.6 | 7.4 | 4 | | 2.9 | 2.8 | 1 | 0.8 | 5.6 | 3.6 | 2 | | 16.0 | 13.1 | 3 | | 11.5 | 5.9 | 1 | 1.0 | 7.9 | 5.4 | 2 | | 10.0 | 6.7 | 3 | | 9.6 | 6.2 | 4 | | 4.7 | 3.2 |
Table 2: Calculations of Averages Concentration of Sucrose Solution (M) ±0.2 ml | Average Initial Mass of Potato Core Slice(g) ±0.1 | Average Final Mass of Potato Core Slices (g) ±0.1 | Change in Mass (g) ±0.1 | Percentage Change in Mass (%) | Standard Deviation of Initial Mass | Standard Deviation of Final Mass | 0.0 | 7.6 | 9.2 | 1.6 | 22.3 | 1.9 | 2.4 | 0.2 | 6.6 | 7.1 | 0.5 | 6.5 | 4.6 | 4.6 | 0.4 | 8.3 | 7.7 | -0.6 | -7.2 | 5.9 | 5.7 | 0.6 | 7.6 | 5.7 | -1.9 | -25.2 | 3.5 | 2.2 | 0.8 | 11.0 | 7.5 | -3.5 | -31.7 | 5.2 | 5.0 | 1.0 | 8.1 | 5.4 | -2.7 | -33.2 | 2.4 | 1.5 |
Sample Calculations:
To find average of initial mass of potato core with 0.2M solution:
# 1 + # 2 + # 3 / 3
5.8 + 11.6 +2.5 / 3 = 6.6
To find average of final mass of potato core with 1.0M solution:
# 1 + # 2 + # 3 + # 4 / 4
5.4 + 6.7 + 6.2 + 3.2 / 4 = 5.4
To find change in mass in 0.4M solution:
Final mass – initial mass = change in mass
7.7 – 8.3 = -0.6
To find percentage change in mass in 0.6M solution:
Final – initial / initial x 100
5.7 – 7.6 / 7.6 x 100 = -25.2
Figure 1: The effect of sucrose solution on the mass of potato cores
Figure 1: In the above graph, it’s visible that with an increasing concentration of sucrose solution there is also
Bibliography: Diffusion and osmosis. (n.d.). Retrieved from http://hyperphysics.phy-astr.gsu.edu/hbase/kinetic/diffus.html McGraw-Hill. (2006). How osmosis works. Retrieved from http://highered.mcgraw-hill.com/sites/0072495855/student_view0/chapter2/animation__how_osmosis_works.html