mean by autoprotolysis? 30. Mention uses of H2O2. 31. What is Per hydrol & Hyperol? 32. Lithium reacts with water less vigorously than sodium. Give your reason 33. Explain the Biological importance of Mg & Ca. 34. What happens when Magnesium burnt in air? 35. Describe the importance of Plaster of Paris. 36. Describe the important uses of Caustic Soda‚ Sodium Carbonate & Quick lime. 37. Explain inert pair effect. 38. Give the formula of Borazine. What is its common
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Li Be B C N O F Ne Lithium Beryllium Boron Carbon Nitrogen Oxygen Fluorine Neon 3 23 4 24 5 27 6 28 7 31 8 32 9 35.5 10 40 Na Mg Al Si P S Cl Ar Sodium Magnesium Aluminium Silicon Phosphorus Sulphur Chlorine Argon 11 39 13 70 14 73 15 40 16 79 17 80 18 84 12 45 48 51 52 55 56 59 59 64 65 75 K Ca Sc Ti
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0225M persulphate and 250 cm3 of 0.4M potassium iodine against a 50 cm3 solution of 0.01 M solidum thiosulphate‚ using 3 ml of 2% starch as an indicator. For part 2‚ a solution of 25cm3 of iodine and persulphate‚ and 25 cm3 of 0.04M potassium chloride was titrated against the same amount of thiosulphate. Using the titre values Tt (ml)‚ time (s) and Tinf‚ graphs were plotted in order to obtain the rate constants k’‚ k’’ and hence ‘n’‚ the reaction order. For part 1‚ a value of 0.96 was obtained
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of potassium manganate(VII) What is observed? A B C D 2 a colourless layer below a purple layer a colourless liquid with the purple crystal unchanged a purple layer below a colourless layer a uniformly purple solution A student adds aqueous sodium hydroxide or aqueous ammonia to aqueous solutions of four different metal compounds. Which solution contains Zn2+ ions? add a few drops of NaOH(aq) ppt ppt ppt no ppt add excess NaOH(aq) ppt dissolves ppt dissolves ppt no ppt add a few drops of NH3(aq)
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formed. Aqueous hydrogen ions (H+(aq)) from the acid react with the hydroxide ions (OH-(aq)) from the alkali‚ forming water. For hydrochloric acid and sodium hydroxide: H+(aq) + Cl-(aq) + Na+(aq) + OH-(aq) → Na+(aq) + Cl-(aq) + H2O(l) Hydrochloric acid Hydrochloric acid Sodium Chloride Sodium Chloride Sodium Hydroxide Sodium Hydroxide Neutralization is an exothermic reaction which means it gives out energy to the surroundings in the form of heat. There’s only a chemical reaction
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TABLE OF CONTENTS 1. IA (Alkaline Metals) 1.1. H………………………………………………………………………..2 1.2. Li………………………………………………………………………..2 1.3. Na………………………………………………………………………2 1.4. K………………………………………………………………………..3 1.5. Rb………………………………………………………………………3 1.6. Cs………………………………………………………………………3 1.7. Fr……………………………………………………………………….4 1. IIA (Alkaline Earth Metals) 2.8. Be………………………………………………………………………4 2.9. Mg………………………………………………………………………4 2.10. Ca………………………………………………………………………4
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acid and then titrated against sodium hydroxide. When the indicator turns from pink to orange‚ the volume of sodium hydroxide used is taken down. After doing some calculations‚ the average percentage of calcium carbonate in toothpaste is 19.2%. This average percentage is relatively close to the expected percentage of 20% thus this experiment is a success. Generally after performing the experiment twice‚ the smaller the mass of toothpaste used‚ the more volume of sodium hydroxide is needed to neutralise
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potassium permanganate into the beaker and record the appearance. For Recrystallization part‚ place approximately 5-7 grams of sodium thiosulfate in a test tube and heat the mixture the solid appears to melt. Then allow the solution to cool to room temperature. If no crystals appear when the test tube is cooled‚ the solution is supersaturated. Next drop one crystal of sodium thiosulfate into the supersaturated solution and describe what happens on the data sheet. The Dialysis section is divided into
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fewer luster. Water: Bubble effect ‚ remained stationary. Size was 4mm x 4mm‚ translucent and more luster than the oil. E. Making iodine in water: potassium iodide (KI)‚ and sodium hypochlorite (bleach‚ NaClO). F. Making iodine in oil: mineral oil‚ water‚ potassium iodide‚ and sodium hypochlorite Initially: H2O in center of oil‚
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following solutions would be. Justify the hypothesis from a chemical standpoint. a. Aqueous Sodium Hydroxide—NaOH (aq) is a very strong base‚ which will completely disassociate into Na+ and OH- ions‚ which would make it a very strong electrolyte. Chemical reaction of the disassociation of Sodium Hydroxide: NaOH (aq)Na+ (aq)+ OH-(aq) b. Aqueous NaCl—Sodium Chloride contains both sodium and chloride ions‚ but in the solid state they are locked in place and therefore unavailable to conduct electricity
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