ions | SO42- | CO32- | C2O42- | IO32- | Mg2+ | S | I | S | S | Ca2+ | I | S | S | I | Sr2+ | S | S | S | I | Ba2+ | I | I | I | S | Key: I- insoluble‚ S-soluble Table II: Color of water (Halide) and Halogen (Hexane) layers | Cl2 | Br2 | I2 | Hexane layer | Clear | orange | Pink | Water layer | Clear‚ colorless | Light gold | Light yellow | Table III: Reactivity of Halogen/Halide Combinations | Cl- | Br- | I- | Cl2 | X | R | R | Br2 | NR | X | R | I2 | NR |
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alternative to synthetic adhesives and reduce waste simultaneously. Scope and Limitations of the Study Only pili nut shells and pulp shall be used in the experiment. The shell and pulp extracts shall be obtained through Soxhlet extraction using Hexane (C6H14) as the solvent. After which‚ the resulting extracts shall be separated from the solvent through distillation‚ separately. The obtained pili nut shell extract and pulp extract shall then be tested in 30%‚ 50% and 70% concentrations. The
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Lab# 3 – Simple and Fractional Distillation Written by: Theressa Payne Partner: Jennifer Jantzi Performed: February 4‚2013 for CHEM 7005 John Birtwell February 6‚ 2013 Lab # 3 – Simple and Fractional Distillation Introduction: One of the most important tasks in chemistry is the separation of organic compounds which are not usually found in pure form naturally or as products of chemical synthesis. Distillation is a common method for purifying liquids based upon their boiling
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A miser is ever in want. --Greek proverb Preparing to experiment You will be provided with the following materials: Redox Reactions Reactions involving oxidation and reduction processes are very important in our everyday world. They make batteries work and cause metals to corrode (or help to prevent their corrosion). They enable us to obtain heat by burning fuels--in factories and in our bodies. Many redox reactions are complex. However‚ combustion and synthesis (from elements) are
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Solubility and Functional Groups _______________________________________________________ You will recall from general chemistry that a solution has two components: the solvent‚ which is the substance present in greater amount‚ and the solute‚ which is dissolved in the solvent. Solubility is defined as the mass (in grams) of solute dissolved in 100 g of solute at saturation. Molar solubility is defined as the amount (in moles) of solute per liter of saturated solution. The solubility of one compound
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My results were surprising because I didn’t expect that much difference results from internet and mine. The results for Hexane for example was much quicker than I expected‚ I found that it boiling point was 60C but in my experiment it was 30 C it’s the double of what it should be. Most of the sample like methanol and ethanol was pretty clos to the result that I found on internet. The trial that I did was Butanol again with the hot plates and it took of course much longer to boil and it started
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efficient. The most important aspect of the recrystallization technique is the selection of the solvent. A large number of solvents are commonly used for recrystallization of organic compounds. Among these are water‚ ethanol‚ ethyl ether‚ methanol‚ and hexane to name just a few. A solvent‚ which works beautifully for one recrystallization‚ may be totally unsuitable for purification of a different compound - the choice for recrystallization solvent is made on a case-by-case basis. This is because of the
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Analysis of Hydrocarbons Jennifer Alambra‚ Ma. Nancy Anulat‚ Alfonso Apepe*‚ Jacqueline Arsenal 3Bio4 Department of Biological Sciences - College of Science‚ University of Santo Tomas‚ Manila ABSTRACT The unknown hydrocarbon sample was differentiated and characterized by the use of three tests. The outcomes of these tests are as follows: Nitration test (negative)‚ Bromine test (positive) and Basic Oxidation test (positive). From these results the unknown sample can be classified
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HKCEE Chemistry 2007 Paper 1 Section A 1. A is a compound formed from oxygen and magnesium‚ while B is a compound formed from oxygen and fluorine. a) Draw the electronic diagram of A‚ showing electrons in he outermost shells only. (1) b) Draw the electronic diagram of B‚ showing electrons in the outermost shells only. (1) c) Compare the melting points of A and B. Explains your answer. Melting point of A is higher than that of B. Ions of A are linked by strong ionic bonds /
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substances namely Hexane‚ Eugenol‚ Unknown hydrocarbon 1‚ Unknown hydrocarbon 2‚ and Acetylene gas was used for the selective reactivity of hydrocarbons to functional group tests; Bayer’s test‚ Bromine test light‚ Bromine test dark‚ and Tollen’s test. In Bayer’s test‚ only Acetylene‚ Eugenol and Unknown hydrocarbon 2 reacted positively and the rest retain the purplish color of KMnO4. On the other hand‚ the five compounds in Bromine test with light reacted positively. In Bromine test dark‚ Hexane and Unknown
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