CHAPTER 1: Introduction‚ Measurement‚ Estimating Answers to Questions 1. (a) Fundamental standards should be accessible‚ invariable‚ indestructible‚ and reproducible. A particular person’s foot would not be very accessible‚ since the person could not be at more than one place at a time. The standard would be somewhat invariable if the person were an adult‚ but even then‚ due to swelling or injury‚ the length of the standard foot could change. The standard would not be indestructible – the foot would
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½(vo + v) v = vo – gt y = vot – ½gt2 v2= vo2 – 2gy R = (v02/g)sin(2θ) Forces Fnet = ma Fgravity = mg Ffriction ≤ μsN Ffriction = μkN Circular Motion Fnet = mv2/r ac = v2/r v = 2πr/T f = 1/T T = 1/f Gravitation F = GM1M2/R2 g = GM/R2 T2/R3 = 4π2/GM = constant GM = Rv2 Energy W = Fdcosθ KE = ½mv2 PE = mgh PE = ½kx2 PE0 + KE0 + W = PE + KE P = W/t = E/t = Fv Momentum p = mv ptot = p1 + p2 +
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Physics Equations and Formulas By Steven Holzner Part of the Physics I For Dummies Cheat Sheet Physics is filled with equations and formulas that deal with angular motion‚ Carnot engines‚ fluids‚ forces‚ moments of inertia‚ linear motion‚ simple harmonic motion‚ thermodynamics‚ and work and energy. Here’s a list of some important physics formulas and equations to keep on hand — arranged by topic — so you don’t have to go searching to find them. Angular motion Equations of angular motion are
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Conceptual Physics 11th Edition Chapter 1: ABOUT SCIENCE © 2010 Pearson Education‚ Inc. This lecture will help you understand: • • • • • • • • What Science Is Scientific Measurements Mathematics—The Language of Science Scientific Methods The Scientific Attitude Science‚ Art‚ and Religion Science and Technology Physics—The Basic Science © 2010 Pearson Education‚ Inc. What Science Is Science • is a body of knowledge. • is an ongoing human activity. • has beginnings
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Discuss your physics questions online at www.physics4spm.com 3 FORCES AND PRESSURE 3.1 UNDERSTANDING PRESSURE Pressure is force per unit area Pressure = Force Area P= F A 1. Define Pressure 2. State pressure’s formula 3. State relationship between pressure and area. 4. Describe applications involving High Pressure Increasing the pressure by reducing the area A sharp knife has a very The studs on a football small surface area on its boot have only a small cutting edge so that high area of contact
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I did not understand how to explain why temperature does not change during a phase change and am not entirely sure if I have accurately or thoroughly described 3.2.3 and 3.2.4. This is also the case for 3.2.12 Thermal Physics Thermal Concepts: Temperature (T) is a measure of how hot or cold an object is‚ and it is the temperature that determines the determines the direction of thermal energy transfer between two objects. It is a scalar quantity and is measure in degrees celcius (°C
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Score: 139.70 1. out of 140 points (99.79%) award: 10 out of 10.00 points Exercise 3-1 Classifying adjusting entries LO C3 In the blank space beside each adjusting entry‚ enter the letter of the explanation A through F that most closely describes the entry. A. B. C. D. E. F. To record this period’s depreciation expense. To record accrued salaries expense. To record this period’s use of a prepaid expense. To record accrued interest revenue. To record accrued interest expense. To record the earning
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1.1. Equations and Graphs In each of problems 1 - 4‚ find (a) an ordered pair that is a solution of the equation‚ (b) the intercepts of the graph‚ and (c) determine if the graph has symmetry. 1. 2. 3. 4. 5. Once a car is driven off of the dealership lot‚ it loses a significant amount of its resale value. The graph below shows the depreciated value of a BMW versus that of a Chevy after years. Which of the following statements is the best conclusion about the data? a. You should
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Physics 103 Equations a2 + b2 = c2 If v = ∆x ¯ ∆t |g| = 9.8m/s2 1 K = 2 mv 2 Wnet = ∆K 2 |acent | = vtang /r ω = 2πf = 2π T sin θ = opposite hypotenuse cos θ = adjacent hypotenuse tan θ = sin θ/ cos θ b x = −b± 2a −4ac v = v0 + at p = mv ¯ P =W t Wcons = −∆U P I = 4πr2 Fspr = −k ∆x √ 2 ax2 + bx + c = 0 then 1 a = ∆v ¯ ∆t x = x0 + v0 t + 2 at2 Fext = ma = ∆p w = mg ∆t W =F s Ug = mgy ME = U + K M Ei + Wother = M Ef |τ | = rF⊥ v = fλ P = F/A Uspr = 1 kx2 2 1 4π 0 e = 1.6 × 10−19
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PROPONENT TABLE OF CONTENT Chapter 1 (Problem and its Settings) a. Background of the Study. b. Statement of the Problem. c. Assumption. d. Scope and Limitation. e. Significance of the Study. Chapter 2 (Analysis of the existing & Propose Systems) a. Procedure of the existing system. b. Analysis of the existing system. c. Problems encountered in the existing system. d. Procedures in the existing system. e. Analysis of the Proposed System. f. Benefits of the Proposed System. Chapter 3 (Review of Related Literature
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