STA304 H1 S/1003 H S Winter 2013 Dragan Banjevic (I) Note: A lot of material will be used from Internet‚ some with reference‚ some without. 2 CITY OF TORONTO NEIGHBOURHOODS 1 West Humber-Clairville 19 Long Branch 36 Newtonbrook West 54 O’Connor-Parkview 2 Mount Olive-SilverstoneJamestown 20 Alderwood 37 Willowdale West 55 Thorncliffe Park 3 Thistletown-Beaumond Heights 21 Humber Summit 38 Lansing-Westgate 56 Leaside-Bennington 4 Rexdale-Kipling
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it was found that 40% of young people failed a standard fitness test. A random sample of 30 young people is taken. (i) Explain why‚ for such random samples‚ the mean number of those who failed the fitness test is 12. [1] (ii) Find the probability of the mean number occurring. Explain how you would check whether the mean is also the modal value. No further calculations are necessary. [4] A local health authority wishes to investigate whether or not the proportion of young
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Pro-max. Method: Measure and record the dimensions of the cross sections of the test specimen; Clamp up specimen in the crossheads of machine and run the test. Set distance between grips 100 mm Perform five tensile tests. Determine the mean and standard deviation of the samples tensile strength (maximum stress from stress-strain curve). Impact testing of thermoplastics. Standard ASTM D 256 (US standard)‚ ISO 180 (International standard). Testing
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Alcohol consumption in sexually frustrated fruit flies Drosophila melanogaster Ankit Sharma April 8‚ 2013 BIO 534 Introduction The fruit flies Drosophila melanogaster show addiction-like behavior towards alcohol where the flies seem to be physiologically dependent on (Atkinson et. al.‚ 2012). The flies can thus exhibit a cognitive dependence where such behavior is stored in memory and same behavior is also shown in the future. This addiction is linked to NPY neuropeptide levels which can
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out because it had a 2.63% chance of 1st year costs exceeding $37M. The other 3 policies had minimal risk of exceeding $37M: o CTC = 0.03% o HIC = 0.0% o RCNC1 = 0.03% • RCNC2 was ruled out because it had expected 5 year total costs of $113.7M (mean) which was substantially higher than CTC or HIC; 5 year total expected costs for each of the remaining two carriers were not significantly different. o CTC = $65.24M o HIC = $67.59M • Each of the remaining policies‚ CTC and HIC‚ has advantages and
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repeated readings were not similar then the odd one out would be an outlier. I would then either repeat this experiment and substitute the new resistance value for the outlier OR simply leave out the outlier value when calculating the mean average. To calculate the mean average I would add up the 3 resistance values from each temperature and then divide by 3. 4. The temperature and the range was from 20OC to 60OC (select the temperature range you used) Yes this was a suitable range as the graph showed
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footage that contains resort-specific and region-specific footage regarding the most popular honeymoon destination resorts including: Hawaiian Islands‚ Caribbean Islands‚ Mexico and Florida. The marketing of destinations serve to guide newlyweds by means of capturing videos –including rating each resort based on the most important characteristics such as view‚ cost and accommodations. These footages attempt to generate an attractive‚ fascinating and informative product on what the newlyweds can expect
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08 ETHE AUSTRALIAN NATIONAL UNIVERSITY SCHOOL OF FINANCE AND APPLIED STATISTICS First Semester Examination 2010 QUANTITATIVE RESEARCH METHODS (STAT1008) Writing Period: 3 hours duration Study Period: 15 minutes duration Permitted Material: Non-programmable calculator‚ dictionary and 1 A4 page with notes on both sides Instructions to Candidates: • Attempt ALL questions. • Each question is of equal mark value. • Start your solution to each question on a new page. • To ensure full marks
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1 of 25 Let X represent the amount of time it takes a student to park in the library parking lot at the university. If we know that the distribution of parking times can be modeled using an exponential distribution with a mean of 4 minutes‚ find the probability that it will take a randomly selected student more than 10 minutes to park in the library lot. | 0.917915 | | 0.670320 | | 0.329680 | | 0.082085 | 6 out of 6 Correct!! Question 2 of 25 On the average‚ 1.8 customers
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A. Get the Big Picture: At Manzana the new policies (RUNs) are believed to be more profitable because they “commanded the highest premiums” and also because they considered that costumers would renew their policies anyway so they didn’t need to pay as much attention to the RERUNs. Nevertheless‚ we consider that these are not the most profitable policies and for instance they should not be given high priority. Table 1: Manzana Profit for 2nd quarters Looking at the profits we can see that there
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