Regents Physics Constant Velocity/ Acceleration Lab 10-3-13 Problem: Graphical Analysis of Constant Velocity and Accelerated Motion. Theory: Gravitational acceleration is constant on Earth g=9.8m/s2 Therefore‚ when the golf ball is dropped‚ the acceleration will be equal to gravitational acceleration agb=9.8m/s2 Given there is no air resistance‚ this means that when the golf ball is dropped from a given distance‚ according to the formulas‚ the golf ball will accelerate
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experiment will show how to determine the linear motion with constant (uniform) velocity particularly the dynamic cart and linear motion with constant (uniform) acceleration‚ (e.g. free fall of motion). At the end of the experiment we found out that the velocity is a speed that involves direction of an object as well as the time. While for the acceleration‚ it is directly proportional to the distance or height but inversely proportional to the time. By close observations‚ recording of data and right computations
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The experiment that was conducted was primarily about Newton’s second law of motion. Newton’s second law of motion states that a net force is required for a body to have acceleration. If a net force is applied on an object‚ then the object will accelerate with respect to the direction of the said force. The body’s acceleration is directly proportional to the net force and inversely proportional to its mass. The experiment conducted was used to verify the relationships specified in Newton’s second
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two-experiment laboratory‚ students ideally will know how to analyze displacement‚ velocity‚ and acceleration in terms of time for objects in motion with a constant acceleration in a straight line. In addition‚ students will master how to calculate the slope of a displacement-time graph to determine the velocity of an object in motion at a constant velocity and the slope of a velocity-time graph to determine the acceleration of an object. Materials In experiment 1‚ students prepare two strips of paper tape
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Prac Report Problem: How does the increase mass affect acceleration and the force of the accelerating object? Purpose: The purpose of the practical is to find how mass affects acceleration and how it affects also the force of the accelerating body. To do this we are going to do the ticker tape experiment where an accelerating body pulls a tape through a consistent 50 dot per second ticker timer. The acceleration body in this experiment will be a small trolley pulled by a string that is pulled
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Picket Fence Free Fall Harrison Leeman Josh Dehaan‚ and Nick Edwards Monday November 04‚ 2012 Mr. Hutchinson SPH 3U Purpose: To measure the acceleration of a freely falling object (g) to better than 0.5% precision using a Picket Fence and a Photogate. Materials: Computer‚ Vernier computer interface‚ Logger Pro‚ Vernier Photogate‚ Picket Fence‚ and a clamp or ring stand to secure Photogate. Procedure: See Lab Sheet Preliminary Questions:
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Background Information The Giant Drop The Giant Drop is a vertical free fall‚ looming 119m meters above the ground. Carried by a mechanical lift to the very top‚ it then plummets‚ reaching up to 135km/hr due to the acceleration of gravity‚ before finally coming to a stop with the magnetic braking system (Burton‚ 2009). A rider on this type of design will experience three phases of apparent weight: the lifting‚ falling and braking stages. At first‚ the rider will feel
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Introduction To graphically analyze motion‚ two graphs are commonly used: Displacement vs. Time and Velocity vs. Time. These two graphs provide significant information about motion including distance/displacement‚ speed/velocity‚ and acceleration. The displacement and acceleration of a moving body can be obtained from its Velocity vs. Time graph by respectively finding the area and the slope of the graph. Data Tables – Part I Displacement (m) Time (s) 0.10 m 0.37 s 0.20 m 0.586 s 0.30 m 0.761 s 0
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particle starts from the origin at t = 0 with a velocity of 6.0[pic] m/s and moves in the xy plane with a constant acceleration of (-2.0[pic] + 4.0[pic]) m/s2. At the instant the particle achieves its maximum positive x coordinate‚ how far is it from the origin? [pic] 2 At t = 0‚ a particle leaves the origin with a velocity of 5.0 m/s in the positive y direction. Its acceleration is given by [pic] = (3.0[pic] - 2.0[pic]) m/s2. At the instant the particle reaches its maximum y coordinate how far
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being applied to the object should appear on that object’s free-body diagram. We should include a downward normal force‚ applied to the elevator by you. Yes‚ mg is numerically equal to this normal force in this case. When the system has an acceleration‚ however‚ these forces are no longer equal. The system has a constant velocity directed up When the system of you and the elevator is moving up with a constant velocity‚ what do we need to change on the freebody diagrams? 1. An extra
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