Sound In Air Lab
Speed of Sound in Air
By: James Chen
Lab Partner: Jin Zhang and Jake Salpeter Phys 130, Lab section: EE11
TA: Khaled Elshamouty
Date of lab: October 29, 2013
Introduction
Sound is a longitudinal (compressional) wave caused by a vibrating source. In this experiment, we use standing sound waves created by the tuning forks to determine the speed of sound in air in a tube when it reaches different resonances. In this lab we focused primarily on using standing sound waves (compressional waves) created by tuning forks in order to determine the speed of sound in air in a tube when it reaches resonance.
v=λf v speed of sound in a medium (m/s) wavelength of the waves (m)
frequency of the sound source vibrations (Hz) …show more content…
Strike the tuning fork with the rubber rod and hold it at the open end. Slowly move the plunger back into the tube until aloud amplification of the tone is hear. It might be necessary to strike the tuning fork several times in order to keep the tuning fork vibrating. Adjust the plunger for maximum amplification and this would be the first resonance point. Measure the length of the standing wave column. Then, continue pulling out the plunger till you hear the second maximum amplification point and third if possible. These length correspond to D1, D2, D3 for n = 1, 2, 3, and etc. Repeat the steps for the other three tuning forks and record all the data and do all the related …show more content…
Part four,
Calculations for the theoretical approximation for the end correction Xo using the above equation:
The theoretical and experimental values for the end correction do agree within error.
Question:
Part one,
At the closed end of the pipe, there must be a node because there is no motion occurring at the end of the pipe and there is no displacement, the air molecules cannot move.
If the pipe was closed at both ends, L1 = /2 and L2 = ,
therefore, L2/L1 = 2
Part two,
If the pipe was closed at one end as used in the experiment, then
This ratio of the single open-ended pipe is 1.5 times larger than the pipe closed at both ends. This means that in order to produce the same harmonic, the single-open ended pipe needs to be 1.5 times larger than the pipe closed at both ends.
Part three,
The first resonance occurs at, the maximum length is the tube length which is 1.000m ± 0.0001m. Therefore, in order to find the lowest frequency, we need to find the largest, and the maximum length will produce the largest. So, and.
By: James Chen
Lab Partner: Jin Zhang and Jake Salpeter Phys 130, Lab section: EE11
TA: Khaled Elshamouty
Date of lab: October 29, 2013
Introduction
Sound is a longitudinal (compressional) wave caused by a vibrating source. In this experiment, we use standing sound waves created by the tuning forks to determine the speed of sound in air in a tube when it reaches different resonances. In this lab we focused primarily on using standing sound waves (compressional waves) created by tuning forks in order to determine the speed of sound in air in a tube when it reaches resonance.
v=λf v speed of sound in a medium (m/s) wavelength of the waves (m)
frequency of the sound source vibrations (Hz) …show more content…
Strike the tuning fork with the rubber rod and hold it at the open end. Slowly move the plunger back into the tube until aloud amplification of the tone is hear. It might be necessary to strike the tuning fork several times in order to keep the tuning fork vibrating. Adjust the plunger for maximum amplification and this would be the first resonance point. Measure the length of the standing wave column. Then, continue pulling out the plunger till you hear the second maximum amplification point and third if possible. These length correspond to D1, D2, D3 for n = 1, 2, 3, and etc. Repeat the steps for the other three tuning forks and record all the data and do all the related …show more content…
Part four,
Calculations for the theoretical approximation for the end correction Xo using the above equation:
The theoretical and experimental values for the end correction do agree within error.
Question:
Part one,
At the closed end of the pipe, there must be a node because there is no motion occurring at the end of the pipe and there is no displacement, the air molecules cannot move.
If the pipe was closed at both ends, L1 = /2 and L2 = ,
therefore, L2/L1 = 2
Part two,
If the pipe was closed at one end as used in the experiment, then
This ratio of the single open-ended pipe is 1.5 times larger than the pipe closed at both ends. This means that in order to produce the same harmonic, the single-open ended pipe needs to be 1.5 times larger than the pipe closed at both ends.
Part three,
The first resonance occurs at, the maximum length is the tube length which is 1.000m ± 0.0001m. Therefore, in order to find the lowest frequency, we need to find the largest, and the maximum length will produce the largest. So, and.