Detection of Ions in Solutions Using Acid/Base Chemistry: A Quality Control Test Objective: This lab focuses on the detection of ions using titration as an analysis tool. You will standardize NaOH and HCl solutions so that you know the exact concentration and then prepare samples of common household items in order to determine the amount of calcium in Tang®‚ Mg(OH)2 in Milk of Magnesia‚ etc. You will learn to prepare samples of a specified concentration‚ learn about acids and bases through
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Science Coursework-Rates of Reactions Introduction Investigating how the concentration of sodium-thiosulphate (STS) and hydrochloric acid (HCL) affects the rate of reaction in the experiment. In addition I am also checking how different variables affect my experiment and also how I can make my test more precise‚ reliable and accurate. Strategy According to my results‚ as the concentration of STS solution increased the rate of reaction of my experiment was increased. Also as the concentration
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part B the relative rate of diffusion of two different gases at the same temperature is given by the relationship: r1 /r2 = (M2 / M1)1/2 Once the two different gases meet‚ in this case they are HCl and NH3 ammonium chloride will appear‚ HCl(g) + NH3(g) ------> NH4CL(s) ! ! ! ! ! ! ! EQ. I1 EXPERIMENTAL METHODS Please refer to the Poe‚ Judith CHM110F course manual‚ experiment 2: Behavior of Gases on page 42 - 46. No deviations were made.
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I. Introduction The purpose of this experiment is to determine the pH values of acids‚ bases‚ and buffers of distilled water and 10.0 buffer using measured concentrations of Sodium hydroxide (NaOH) and/or Hydrochloric acid (HCl). Acid is a compound typically having a bitter taste and capable of nullifying alkalis and releases hydrogen ion when added to a solution‚ or containing an atom that can accept a pair of electrons from a base (McKinley‚ Dean O’Loughlin‚ & Stouter Bidle‚ 2016). Bases are water-soluble
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Investigation 14 Chemistry 113 Lab 10/13/2011 1) Method 1: Adding acid NaHCO3 + HCl → NaCl + CO2 + H2O a) Unknown mixture of NaCl and NaHCO3 Mass of unknown mixture (NaCl + NaHCO3) | 3 g | Mass of HCl | 30 .31g | Mass of products ( NaCl + H2O ) | 26.98 g | Calculate mass of CO2 | 6.33g | Calculate mass of NaHCO3 | 12 .1 g | i) Calculation : Mass of CO2 = [Mass of unknown mixture (NaCl + NaHCO3) + Mass of HCl ] – [Mass of NaCl + H2O] = (3 g + 30.31 g) – 26.98 g = 6.33g Mass of NaHCO3
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Based on my observation CaCl2 is soluble in water. 2. When 15% of HCl was added to CaCl2 as the teacher was performing the experiment I observed and realized some changes took place physically. It was physical change because the color was clear. 3. By adding 15% of HCl of CaCo3 ‚ made it change chemically‚ I would tell this by effervescence and observation. 4. The most obvious difference is that when CaCl2 was mixed with 15% HCl it changed physically and the solid remain on the filter paper is
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to acetone and HCl and find a value for the rate constant‚ k. Since the concentrations of acetone and HCl are much higher than that of I2‚ the concentrations of acetone and HCl will change very little. Thus the rate will be determined by the time needed for iodine to be used up. Iodine has color so you can easily follow changes in iodine concentration visually. The equation‚ rate = k(A)m(H+)n(I2)p‚ can be simplified to rate = k[I2]/t since the values for acetone and HCl essentially remain
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1411-76426| Data Tables: Part 1: |Chemicals|Well No.|Observations of the Reaction| A.|NaHCO3 + HCl|1 |clear bubbles formed| B.|HCl + BTB|2 |turned orange after BTB was added‚ transparent‚ acidic| C.|NH3 + BTB|3 |turned dark blue after BTB was added‚ opaque‚ basic| D.|HCl + blue dye| |blue dye was missing from kit| E.|Blue dye + NaOCl| |blue dye was missing from kit| | with the 1 drop of HCl| || F.|NaOCl + KI|4 |small white precipitate‚ color changed to black after starch was added |
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Introduction In this chemical reaction‚ the magnesium will dissolve in the hydrochloric acid to produce hydrogen gas. This is because magnesium is higher than hydrogen in the reactivity series. Therefore‚ when the two reactants are combined‚ a displacement reaction occus and the magnesium displaces the hydrogen‚ forming magnesium chloride and hydrogen gas. Mg (s) + 2HCl (aq) -> MgCl 2 (aq) + H 2 (g) Magnesium + Hydrochloric acid -> Magnesium Chloride + Hydrogen
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concluded with 0.54M of NaOH. The results of trial 1 and 3 resemble the most similar and consistent to the expected results of the experiment. Discussion of Theory: The lab as able to determine the concentration of NaOH by neutralizing the solution with HCl‚ a solution which its concentration was already known‚ this process is called titration. It works by neutralizing a solution from a weak acid/base and its
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