retailing downturn. Higher-than-expected inventory was being carried through the peak season as well. This was their peak sales period and it was hoped that proceeds from this season would pay off the seasonal loan for the capital expenditure. SureCut Shears now faced a credit problem because they no longer expected to be able to pay off the seasonal loan. INTERPRETATION OF EXHIBITS Due in part to a slackening of sales‚ inventory at the end of March 1996‚ the amount of additional money tied up in inventory
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Section 3 BS 8110-1:1997 3.5.5.2 Shear stresses The design shear stress v at any cross-section should be calculated from equation 21: V v = -----bd equation 21 In no case should v exceed 0.8Æfcu or 5 N/mm2‚ whichever is the lesser‚ whatever shear reinforcement is provided. 3.5.5.3 Shear reinforcement Recommendations for shear reinforcement in solid slabs are given in Table 3.16. 3.5.6 Shear in solid slabs under concentrated loads The provisions of 3.7.7 may be applied. 3.5.7 Deflection Deflections
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Company: Fischer is both treasurer and president • Stewart did approve the 2‚5mill loan extension • House hold scissors and industrial shears • Severe competition from foreign companies • Made profits every year since 1958 • Short term borrowing were normally between july and December‚ additional capital neeede to support sales peak • Produce at an even rate throughout the year – contributed to the need of seasonal funds • June 1995 • 3‚5 mill loan- anticipated to pay it of in decemebr
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Part 1: For and athlete in a sport of your choice design a 12 week strength and conditioning training programme. 12 Week Strength and Conditioning Programme Player history and stats The programme has been designed for a professional football (soccer) player to return from a left grade 2 adductor magnus tear whilst striking the ball in a competitive game. The player has been cleared through the club doctor and his physio to take part in the programme. The player is currently 6 weeks post
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Chapter 1 General concepts of stress and strain • The end of the chapter‚ the students should be able to: – Find internal forces of a body – Calculate the average normal stress and average shear stress of a body subject to axial forces and shear forces respectively – Calculate the normal strain from a body`s deformation – Understand and be able to apply the relationship between stress and strain. – Locate and identify material characteristics associated with a tensile test stress-strain diagram
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This experiment highlights the procedure to determine such properties as modulus of elasticity in shear and the torsion yield strength. During the experiment‚ aluminium and mild steel was used to demonstrate how the materials behave during the testing condition. By measuring the applied torque with respect to the angle of twist‚ the Torsional rigidity (GJ)‚ the Modulus of Rigidity (G) and the shear yield stress (τ) for ductile materials‚ mild steel and aluminium. INTRODUCTION The purpose of this
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audience on how to shear a sheep before their show Shearing sheep is fun and very easy if you know what you’re doing. I have sheared a lot of sheep within the past five years‚ and I have taken lambs to the fair. I learned how to shear my first year lamb. Ed Smolder‚ the old 4-H county extinction agent always helped out at the fair shearing the sheep. He once told me that I needed to flip the lamb and sheer it or go into the ring with your lamb looking nasty. I had to learn how to shear by myself‚ so
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same time. The wing design will be optimized. Before processing the wing design‚ it is necessary to understand the structure of the wing. In the figure-x ‚ it shown the elements and layout of wing structure of the Pilatus PC9/A which include spars‚ shear webs‚ ribs‚ skin and skin stingers. This section will be process the design of those elements base on the loads calculated in section 4. Note that the calculation is for one wing only as the load same for both wings as assumed. Figure xx: The wing
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[(1 – v) εz + v(εx + εy)] F.S = Actual strength σutsRequired strength σw Pressure vessels Hoop stress (cyl.) Longitudinal (sph.) P=Int. pressure‚ t=thickness σ1 = Prt σ2 = Pr2t σ1 = 2σ2 Shear Stress & Strain Pure shear Mod of rigidity τ = shear force vx-area A εx= εy= εz = 0 Strain
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