Assume that g = 10 m/s2. Time to reach apex 18/10 = 1.8 Time x 2 = 3.6 Great height reached by ball – (Velocity)(time)+(-5)(time^2) 18x1.8+(-5)(1.8^2)=16.2 A model rocket accelerates upward from the ground with a constant acceleration‚ reaching a height of 63 m in 8 s. * Speed at height 63 - 2x63/8 = answer What is the acceleration= answer/8 * If you were to drop a rock from a tall building‚ assuming that it had not yet hit the ground‚ and neglecting air resistance‚ after 5.5 s; * How
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of 110 m. Determine the acceleration of the car. ------------------------------------------------- Solutions Given: d = 110 m | t = 5.21 s | vi = 0 m/s | | Find:a =?? | d = VI*t + 0.5*a*t2 110 m = (0 m/s)*(5.21 s) + 0.5*(a)*(5.21 s)2 110 m = (13.57 s2)*a a = (110 m)/ (13.57 s2) a = 8.10 m/ s2 ------------------------------------------------- Equations and Problem-Solving * Rocket-powered sleds are used to test the human response to acceleration. If a rocket-powered sled is accelerated
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PBSC Math Science Institute Physics Course 2014 - Rocket Lab Report Title: RockSim and Electronic Altimeter Measurement Techniques Name: Scarlet Henriquez Email: scarletpatricia94@aol.com LAB SESSION ___8____Assignment _____7_____ Due Date: ___7/8/14______ Objective: Launch a smaller rocket to learn how to compare RockSim predictions (computer based) to an actual instrument measurement carried by the rocket (Electronic Altimeter). This Lab shows how better the
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= speed of balloon‚ v. by using the equation [Answer: 12.1 ms–1] 2. A car and train moves together along two parallel paths at 25.0 ms–1. The car then undergoes a uniform acceleration of -2.5 ms–2 because of a red light and comes to rest. It remains at rest for 45.0 s‚ then accelerates back to a speed of 25 m s – 1 at a rate of +2.5 ms–2. How far behind the train is the car when it reaches the speed of 25 ms–1‚ assuming that
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Question: 1. Which person(s) changes direction during the time of motion? 2. Which person(s) is/are not moving? 3. Which person has the greatest average speed? 4. Which person(s) has/have a constant‚ positive acceleration value? 5. Which person has the greatest magnitude of acceleration? 1. C 2. none 3. E 4. D reason: lets say initial vel = -100‚ and final velocity = -50 -> a = vf – vi/t = -50 – (-100) = +50/t 5. C (largest change in velocity) EXAMPLE
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Duncan‚ Vinny‚ and Wayne are all friends working - or wasting time - the summer before senior year in high school. Duncan is the soul‚ Vinny the brains‚ and Wayne the muscle. At the end of the previous summer‚ Duncan tried to save a drowning girl and failed. Not being a hero has really affected his life‚ particularly his relationship with his girlfriend Kim. Also‚ he is now terrified of swimming‚ especially when the nightmares come back. Duncan’s summer job is with the public transit lost and
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Acceleration of a Ball Bearing on an Inclined Plane Group 3 Block 3 Annie Nguyen‚ Cal Malone‚ Amanda Robotham Purpose of Lab: The purpose of this lab is to understand the motion of a ball bearing on an inclined plane through the graphical relationship between displacement and time. The independent variable in this lab was the displacement change of the ball bearing in meters and the dependent variable was the time in seconds. The control variables in the experiment was the ramp angle
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2: SPEED‚ VELOCITY AND ACCELERATION 2.1 Distance and Displacement • Distance is the total length covered by a moving object irrespective of the direction of motion‚ i.e. only the magnitude is of importance. • Displacement is the distance measured in straight line AND in a specific d__________________. Both magnitude and d_________________ are important. Example 1 A car travels 5 km due east and makes a U-turn back to travel a further distance of 3 km. Find (a) the distance covered‚ (b)
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the board. If it enters with a speed of 450 m/s and emerges with a speed of 220 m/s‚ what is the bullet’s acceleration as it passes through the board? Answer: –550 km/s2 5. A particle confined to motion along the x axis moves with constant acceleration from x = 2.0 m to x = 8.0 m during a 2.5s time interval. The velocity of the particle at x = 8.0 m is 2.8 m/s. What is the acceleration during this time interval? Answer: 0.32 m/s2 6. A package is dropped from a helicopter moving upward
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Chapter 4 Problems 1‚ 2‚ 3 = straightforward‚ intermediate‚ challenging Section 4.1 The Position‚ Velocity‚ and Acceleration Vectors 1. A motorist drives south at 20.0 m/s for 3.00 min‚ then turns west and travels at 25.0 m/s for 2.00 min‚ and finally travels northwest at 30.0 m/s for 1.00 min. For this 6.00-min trip‚ find (a) the total vector displacement‚ (b) the average speed‚ and (c) the average velocity. Let the positive x axis point east. 2. A golf ball is hit off a tee at the
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