A Study on Distribution Management of Hindustan Unilever Limited Submitted To Prof. S Govindrajan By PRADEEP NARAIN SANJEEV KUMAR JHA SATADRU BAGCHI SOUMITRA DHALI g08075 g08086 g08088 g08090 g08095 TARUN KUMAR SAHA 2 Content Page 3 4 5 12 14 16 18 26 33 1. Introduction – Hindustan Unilever Limited 2. Distribution Network of HUL
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expected average outcome over many observations.The common symbol for the mean (also known as the expected value of X) is ‚ formally defined by Variance - The variance of a discrete random variable X measures the spread‚ or variability‚ of the distribution‚ and is defined by The standard deviation is the square root of the variance. Expectation - The expected value (or mean) of X‚ where X is a discrete random variable‚ is a weighted average of the possible values that X can take‚ each value
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standard deviation = square root of variance = sqrt(846) = 29.086 4. If we have the following data 34‚ 38‚ 22‚ 21‚ 29‚ 37‚ 40‚ 41‚ 22‚ 20‚ 49‚ 47‚ 20‚ 31‚ 34‚ 66 Draw a stem and leaf. Discuss the shape of the distribution. Solution: 2 3 4 5 6 | | | | | 219200 48714 0197 6 This distribution is right skewed (positively skewed) because the “tail” extends to the right. 5. What type of relationship is shown by this scatter plot? 45 40 35 30 25 20 15 10 5 0 0 5 10 15 20 Solution: Weak positive linear
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EXERCISES (Discrete Probability Distribution) EXERCISES (Discrete Probability Distribution) P X x n C x p 1 p x BINOMIAL DISTRIBUTION n x P X x n C x p 1 p x BINOMIAL DISTRIBUTION n x 1. 2. 3. The probability that a certain kind of component will survive a given shock test is ¾. Find the probability that exactly 2 of the next 4 components tested survive. The probability that a log-on to the network is successful is 0.87. Ten users
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For you‚ what is normal? After browsing lousily in the blog topics given and after three garbage drafts of different topics‚ at last‚ I found the one topic I really get to put my mind on. Actually‚ it interested me to write about this topic because this is one topic which a friend and I debated about. At that time‚ we had different views on how we say that a certain person is normal. I think everyone is just too normal and ordinary that everyone does different things
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Special Probability Distributions Chapter 8 Ibrahim Bohari bibrahim@preuni.unimas.my LOGO Binomial Distribution Binomial Distribution In an experiment of n independent trials‚ where p is a the probability of a successful outcome q=1-p is the probability that the outcome is a failure If X is a random variable denoting the number of successful outcome‚ the probability function of X is given P X r nCr p r q nr Where q=1-p r=0‚1‚2‚3‚….. X~B(n‚p) The n trials
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Distribution Dossier Samsung Electronics India Limited Sales and Distribution Project By: Rohit Agrawal TABLE OF CONTENTS CONSUMER ELECTRONICS MARKET IN INDIA 4 LEADING COMPANIES 5 LG Electronics Inc. 5 Videocon Industries Ltd 5 Samsung India Electronics Private Limited 5 SAMSUNG ’S DISTRIBUTION CHANNEL 7 Role and key deliverables of channel members 7 Consumer Electronics Distribution 8 CHANNEL MEMBER MANAGEMENT 9 Monetary methods 9 Non monetary methods 9 Target setting mechanism
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Frequency Distribution (A) Introduction 1. Ungrouped data versus grouped data Ungrouped data (Raw data): It is a list of individual observed values of the random variable Grouped data (a frequency distribution): It is a table that displays the data in grouping along with the number of occurrences that fall into each group. 2. The components of a frequency distribution a. Class limits: They identify the inclusive values in a class of a frequency distribution The
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C H A P T E R 6 The Normal Distribution Objectives Outline After completing this chapter‚ you should be able to 1 2 3 Identify distributions as symmetric or skewed. 4 Find probabilities for a normally distributed variable by transforming it into a standard normal variable. Introduction 6–1 Normal Distributions Identify the properties of a normal distribution. Find the area under the standard normal distribution‚ given various z values. 5 Find
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NORMAL DISTRIBUTION 1. Find the distribution: a. b. c. d. e. f. following probabilities‚ the random variable Z has standard normal P (0< Z < 1.43) P (0.11 < Z < 1.98) P (-0.39 < Z < 1.22) P (Z < 0.92) P (Z > -1.78) P (Z < -2.08) 2. Determine the areas under the standard normal curve between –z and +z: ♦ z = 0.5 ♦ z = 2.0 Find the two values of z in standard normal distribution so that: P(-z < Z < +z) = 0.84 3. At a university‚ the average height of 500 students of a course is 1.70 m; the standard
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