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    Two-Variable Inequalities

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    The slope is m= y1 - y2 = 0 – 330 = -330 = -3‚ so the slope is -3. x1 – x2 110 – 0 110 To make it easier to find how many refrigerators and how many TVs can fit in the 18-wheeler‚ it would be best to have a linear equation. To find the linear equation‚ the point-slope form can be used. y - y1 = m(x – x1) This is the point-slope form. y – 330 = -3 (x - 0) The slope is substituted for m and (330‚0) is substituted for x and y. y = -3x + 330 Distributive property is used and

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    demand was expected to grow at an approximated linear rate‚ a linear equation i.e. Y = MX +C with C = 0 was used to estimate the slope to forecast the demand trend. This led us to make our first purchase on Day 88 at station 1. However‚ due to a miscalculation and hesitation‚ the purchase was made too late as the utilization of machine at station 1 had already been maximised at 1.0 on Day 50. The company suffered a loss on Day 55 with a fairly linear trend until the machine at station 1 was bought

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    conditions I believe that the results shown in the distance vs. time graph will have a curve showing increasing speed or in other words‚ increasing velocity over time. Therefore‚ the results shown in the velocity vs. time graph will have a positive linear slope. The acceleration vs. time graph will then have no slope and just a straight line because the change of velocity is relatively constant. In conclusion‚ when the mass of the weight increases‚ the acceleration won’t and only the speed and velocity

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    Week 2 Assignment

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    truck hold 71 refrigerators and 118 TVs? c) Will the truck hold 51 refrigerators and 176 TVs? Kindly consider the five given vocabulary words: Solid line Dashed line Parallel Linear inequality Test point In order to solve the problem‚ we need to be aware that the formula to solve any linear equation is y=mx+b. with the said‚ we can say that we have our y- intercept which is 330. (The ordered pair 0‚330 demonstrates that the y coordinate is 330). Since we have our y- intercept‚ we will

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    Graphical Desc

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    ~ Alternatively using Sturges’s formula No. of class intervals = 1 + 3.3 log(n) where n = No. of observations ~ Determining class interval widths Class width = (Largest Observation – Smallest Observation ) / No. of Classes ~ Shapes of histogram – based on following characteristics 1. Symmetry – the two sides are identical in shape and size with respect to a vertical line drawn down the center of the histogram 2. Skewness – with a long tail extending to either the right (positively skewed) or the

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    Math116 Appendix E

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    Use a math editor (Equation Editor or MathType) to write all math text to insure proper formatting of work and answers. |# | |Show your Work using a math editor and state Final Answer |- pts |+ pts | |1 |Suppose you are at the gas station filling your tank with gas. The function C(g) represents the cost C of filling up | |0 |0 | | |the gas tank with g gallons. Given the equation: [pic]

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    Math 102 Notes

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    these properties are fundamentally important to our understanding of more advanced concepts (tangents‚ slopes‚ derivatives). Skills described in this introductory material will be required in many contexts. 1.1 Geometric ideas: lines‚ slopes‚ equations Straight lines have some important geometric properties‚ namely: The slope of a straight line is the same everywhere along its length. Definition: slope of a straight line: y ∆y ∆x x Figure 1.1: The slope of a line (usually given the symbol

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    Basic Numeracy Skills

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    BASIC NUMERACY SKILLS – A REVISION BODMAS B Brackets first O Orders (ie Powers and Square Roots‚ etc.) DM Division and Multiplication (left-to-right) AS Addition and Subtraction (left-to-right) Do things in Brackets First. [pic] |  |6 × (5 + 3) |= |6 × 8 |= |48 |  | |[pic] |  |6 × (5 + 3) |= |30 + 3 |= |33 |(wrong) | |Example: (Powers‚ Roots) before Multiply‚ Divide‚ Add or Subtract. [pic] |  |5 × 22 |= |5 × 4 |= |20 |  | |[pic] |  |5 × 22 |= |102 |= |100 |(wrong) | | | |

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    reasonable straight-line fit to the points confirms that the chosen model and the data are consistent. Advantages of Cum Hazard Plotting 1. It is much easier to calculate plotting positions for multicensored data using cum hazard plotting techniques. 2. Linear graph paper can be used for exponential data and log-log paper can be used for Weibull data. Disadvantages of Cum Hazard Plotting 1. Commercial Cum Hazard paper may be difficult to find. 2. It is less intuitively clear just what is being plotted.

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    Math Essay 2

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    truck hold 71 refrigerators and 118 TVs or will the truck hold 51 refrigerators and 176 TVs? The book shows a graphing points at (0‚330) and (110‚0). m=y‚ -y =330-0=330=-3 x ‚-x 0-110 -110 This is the first slope is -3. Now we can form a linear equation to write. y‚-y =( x-x) slope point y-330=-3(x-0) y-330=-3x we simplify the parenthesis y=-3x+330 add 330 to each side 3x+y<330 add 3x to each side The graph is a solid line rather than a dashed line indicating that points on the line itself

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