Results: Limiting Reactant: Eq 1 Limiting reactant = Benzoin Theoretical yield of Benzil: Eq 2 Theoretical Yield Benzil | 0.296 g | Mass of Crude Benzil | 0.188 g | Mass of Final Benzil | 0.127 g | % Yield | 43% | % Recovery | 66% | Table 1: Mass of crude/final Benzil‚ % yield‚ and % recovery Percent Yield: % Yield = (Final product/Theoretical product) x 100 Eq 3 = (0.127 g/0.296 g) x 100 = 43% yield Percent Recovery
Premium Stoichiometry Alcohol Carboxylic acid
Precipitation Reaction‚ is to be able to calculate the amount of a second reactant we need to react with the reactant one. You must calculate the amount of the second reactant using stoichiometry to figure out what amount is needed. After the amount is calculated‚ you then can add it to the first reactant and it will give you a full reaction. To figure out what you need you have to use stoichiometry. My calculation for the second reactant was: 1.0g CaCl2*2H2O(1mol CaCl2*2H2O/147g CaCl2*2H2O)(1mol Na2CO3/1mol
Premium Stoichiometry Reagent Yield
By examining one specific example of stoichiometric determination‚ which is: “Stoichiometry and limiting reacting”‚ we found out the different mass proportions in which substance react. In this case‚ we used two common acids for this experiment (HCl‚ and H2SO4) and base NaOH Introduction: For this experiment‚ we use Stoichiometry and limiting reactant. The limiting reactant refers to the reactant that controls the amount of product that is
Premium
Copper-Silver Nitrate Reaction Introduction In this experiment copper wire will be placed in a solution of silver nitrate. This single replacement reaction will produce a blue solution of copper II nitrate and solid silver. By weighing the reactants before the reaction‚ the mass of silver produced can be predicted. This theoretical yield can be compared to the actual yield of silver. Purpose Students will compare the theoretical mass of silver with the actual mass of silver from the single
Premium Silver Stoichiometry Copper
a final product of the double-replacement reaction; it breaks down (decomposes) immediately into two products. (3 points) NaHCO3 + HCl → CO2 + H2O + NaCl 3. The NaHCO3 is the limiting reactant and the HCl is the excess reactant in this experiment. Determine the theoretical yield of the NaCl product‚ showing all of your work in the space below. (5 points) NaHCO3 – The Empty Dish 37.06 (grams) – 24.35 (grams) = 12.71 (grams) NaHCO3 12.71 (grams) NaHCO3
Free Stoichiometry Yield Water
Purpose=The purpose of this lab was to combine reactants‚ which we would pick ourself‚ to make 2 grams of Copper Phosphate and another product. Background: Chemistry is the branch of science that deals with the identification of the substances of which matter is composed. Chemistry has to do with many things we use today. For example‚ fireworks are made by the chemical combining magnesium‚ titanium‚ copper‚ aluminum‚ strontium‚ or other periodical elements. Things also like making plastic‚ jewelry
Premium Chemical reaction Stoichiometry Reagent
observations (Step 8) below: A white powdery substance formed when the two reactants were mixed Table 2: Reaction product data Mass (g) Example Trial 1 Trial 2 Mass of CaCl2 1.00 2.00 3.00 Mass of K2CO3 2.5 g 2.50 2.50 Mass of filter paper 0.8 g 0.80 0.80 Mass of watch glass 38.5 g 38.5 38.5 Combined mass of product‚ filter paper‚ and watch glass 40.2 g 42.3 43.3 Mass of dry product 0.9 g 2.00 3.00 Calculations 1. Determine the limiting reagent for each trial. Show your calculations. (Hint: See the example
Premium Reagent Stoichiometry Calcium
Modbury High School SACE Stage 1 Chemistry Topic 5 Mole Concept and Stoichiometry Assignment 5: Volumetric analysis (titrations)‚ stoichiometry SOLUTIONS Note: Write answers neatly and legibly in your exercise book or on pad paper. ALWAYS include a title and name for your work and clearly indicate each answer. 1. a) 23.08 and 23.00 mL are concordant titre values. Average titre = (23.08 + 23.00) = 23.04 mL 2 b) Ca(OH)2
Premium Acetic acid Titration Laboratory glassware
The calculations completed for this experiment include determining the amount of Na2CO3 needed to do a full reaction. This was calculated through stoichiometry calculations: Molar mass was first calculated for CaCl2*2H2O Ca = 40.078g Cl2 = 35.453g*2 = 70.906g 2H2 = 1.00794g*4 = 4.03176g 2O = 15.9994g*2 = 31.9988g 40.078g + 70.906g + 4.03176g + 31.9988g = 147.01456g or 147.0 g CaCl2 1g CaCl2 * 2H2O x (1 mol CaCl2 *2H2O/147g CaCl2 *2H2O) = 0.0068 mol of CaCl2*2H2O Molar mass was then
Premium Stoichiometry
Explore the relationship between reactants producing a product and product breaking apart to its original reactant. Watch as both reactant and product reach a state of balance. No pressure greater than one another. Collision model provides characteristics of chemical reaction. Molecules must collide in order to react; and Characteristics such as higher concentrations‚ high temperature‚ etc. plays the role of increasing the speed of reaction or having more collisions. Scientists use collision model
Premium Chemical reaction Chemistry Reaction rate