Naphtha are assumed to be stored at 303 K Specific Heat capacity of naphtha is assumed to be 3.5235 kcal/kmol Specific Heat capacity of Hydrogen =(6.62+0.00081T) kcal/kmol K ∆H = ∑ ni ∫ C pi dT = 6.015915 x10 6 kcal hr i Hence heat required to raise their temperature from 303 K to 693 K Assuming that the fuel used is Natural gas (calorific value = 39383.82 kJ/m3) Thus amount of fuel needed to supply this quantity of heat =152.75 m3/hr Heat liberated within the reactor due to reaction = 1414
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Understand and observe the concept of Heat Transfer‚ by measuring the temperature distribution for steady state conduction of energy through a specific efficient unit. • Understand the Fourier Law of heat conduction and the usage of its equation in determining the rate of heat flow via solid materials. II. Theory : The Fourier Rate Equation: When a plane section of ∆x and a constant area A maintains a temperature difference ∆T‚ then the heat transfer rate per unit time by conduction
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is heated‚ it will release much more heat than the popcorn. This will be the result as the Dorito has more mass than Popcorn as well as more carbohydrates. It would take about 4-5 Dorito’s or 15 Popcorn to boil 250mL of water. [Signature of teacher: ________wwt_______________] Variables: Table 1: Independent Variable | Dependent Variable | Controlled Variables | The material was changed from a Dorito chip to a singular piece of popcorn. | The heat of the boiling-tube will be measured
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The Biological Importance of Water Water is perhaps the most important molecule for the survival and life of organisms. On the surface of the planet there is obviously much more area of water than land‚ which shows its significance. The fact that water makes up 60-95% of all living organisms shows the incredible biological importance of water. Water has many uses and roles‚ one of them it being used as a support unit in plants. The uptake of water by plant cells creates a pressure against the rigid
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the top one metre of ice‚ called the active layer. This layer contains both water and mud‚ which both have different viscosities and therefore different specific heat capacities. During the three months of summer‚ when the active layer is visible‚ rocks will embed themselves into it. These rocks have a fairly high specific heat capacity in relation to ice‚ so the ice around it will be melted‚ and the process of percolation will cause a pool of water will form below the rock. As the temperature drops
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printed pages and 1 blank page. SPA SJF4655/CGW T45720/3 © OCR 2008 [H/103/4250] OCR is an exempt Charity [Turn over 2 EQUATIONS efficiency = useful energy output total energy input energy = mass × specific heat capacity × temperature change energy = mass × specific latent heat fuel energy input = waste energy output + electrical energy output power = voltage × current energy supplied = power × time energy (kilowatt hours) = power (kW) × time (h) wave speed = frequency × wavelength © OCR
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occupant to move safely before threatened by smoke Containment • Ensure fire can be contained to smallest possible area Extinguishment • Ensure fire can be extinguished quickly with minimum damage FIRE DETECTION SYSTEM SMOKE DETECTORS HEAT DETECTOR FLAME DETECTOR GAS SENSING DETECTOR Ionisation Dectectors Fixed Temperature Detector Infrared Flame Detector Infrared Flame Detector Photolectic Detector Rate Compensation Detector Ultra Violet Detector Ultraviolet
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M10/4/PHYSI/SP2/ENG/TZ1/XX+ 22106511 Physics standard level PaPer 2 Candidate session number Monday 10 May 2010 (afternoon) 0 1 hour 15 minutes 0 INSTRUCTIONS TO CANDIDATES • • • • • Write your session number in the boxes above. Do not open this examination paper until instructed to do so. Section A: answer all of Section A in the spaces provided. Section B: answer one question from Section B in the spaces provided. At the end of the examination‚ indicate the
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the heat transfer occur: from hot water to cold‚ or from cold water to hot? Answer: The heat transferred from hot water to cold water is due to their potential (temperature) difference. * c. What quantity of heat was transferred from one sample to the other? Answer: Here heat transfer from hot water to cold water. Mass of hot water (m) = 200g Initial temperature (T) = 80˚C Finial temperature (T2) = 60˚C Specific heat of water (s) = 4.18 J/g˚C ∆T=(60-80)℃ = - 20˚C Heat transfer
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1. | | | What is the pressure‚ in atm‚ of a tank of gas with a regulator that reads 1250mmHg? | | | Student Response | Correct Answer | A. | 1.64 | | B. | 490 | | C. | 1.79 | | D. | 0.608 | | E. | 1.25 | | | Score: | 0/1 | | | 2. | | | A 147.9-L sample of dry air is cooled from 88.0°C to 22.1°C while the pressure is maintained at 2.85 atm. What is the final volume in L? (Do not type the units.) | | | Student Response | Correct
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