. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . functions in the package dlnm The function onebasis() . . . . . The function crossbasis() . . . . The function crosspred() . . . . . The function crossreduce() . . . Plotting functions . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
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Given the function Find i) ii) iii) iv) Domain . 2. Determine the domain for the following functions: 3. Mega Company plans to market a new product for RM18.50 per unit. The variable cost is RM14 per unit and the fixed cost is RM2200. Assuming is the quantity of the product: i) ii) iii) 4. Find the total cost function‚ . Find the profit function‚ . Determine whether the company will gain profit or loss if 500 units are sold. Given the quadratic function i) ii)
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WEST AFRICAN SENIOR SCHOOL CERTIFICATE EXAMINATION FURTHER MATHEMATICS/MATHEMATICS (ELECTIVE) AIMS OF THE SYLLABUS The aims of the syllabus are to test candidates on: (i) (ii) (iii) further conceptual and manipulative skills in Mathematics; an intermediate course of study which bridges the gap between Elementary Mathematics and Higher Mathematics; aspects of mathematics that can meet the needs of potential Mathematicians‚ Engineers‚ Scientists and other professionals. EXAMINATION FORMAT There will
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Question 4c By introducing an additional pole 1/(s+alpha) to the system‚ The original transfer function G(s) has a DC gain of 1 and the additional pole has a DC gain of 1/alpha. Therefore‚ the new transfer function G1(s) has a DC gain of 1/alpha The DC gain of the new transfer function = 1/alpha . DC gain Is obtained by applying the final value theorem where limit of s goes to 0. Final value theorem can be applied as it is a stable system. Therefore the system has a larger DC gain when alpha
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A PROJECT REPORT ON CONSUMER PERCEPTION TOWARDS COSMETIC INDUSTRY IN GHAZIABAD (IN CONTEXT TO MEN’S FAIRNESS CREAM) TABLE OF CONTENTS |S.No. |Topic |PageNo. | |1 |Objective |3 | |2 |Introduction
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the integrity of the data and information contained in an EHR? The copy/paste function opens the possibility for fraud‚ medical error and risk for malpractice claims. Fraud could occur when a copy/paste function is used and than an insurance company is billed for the procedure/services 2 or 3 times. When in reality the procedure/service was only completed once. Medical error can occur with the copy/paste function‚ when a nurse reads a chart made by a doctor who copy/pasted instructions or initiates
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not have the ability to function without the CEO providing direct guidance. If this were the case and the business unit had too much freedom‚ the business unit would only hurt the company’s bottom line and ultimately be detrimental to the company. On the other side‚ the business could have managers in place who have the ability to provide resources and who can target strategic objectives with more freedom and insight. The hybrid model would allow the business units to function much more quickly to
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3.2 PRODUCTION FUNCTION OR INPUT-OUTPUT RELATIONSHIP SHORT RUN AND LONG RUN PRODUCTION FUNCTION Production function may be defined as the functional relationship between physical inputs that’s factors of production (land‚ labour etc) and physical outputs that is quantity of goods produced. Thus the production function expresses the relationship between quantity of output and the quantities of various inputs used in production. The physical relationship between a firm’s physical input and output
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2 seconds is -1.6g/s 3) b) = = =22 ∴ from seconds the car moves at an average of 22m/s c) t=4 = =16 ∴ The instantaneous rate at 4s is 16m/s 4a) In order to determine the instantaneous rate of change of a function using the methods discussed in this lesson‚ we would use the formula where h will approach 0‚ and the closer it gets to 0 the more accurate our answer will be. 4b) ∴ =1 Therefore‚ = 1 5a) Therefore
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1. ht= -4.9t2+ 450‚ where t is the time elapsed in seconds and h is the height in metres. a) Table of Values t(s) | h(t) (m) | 0 | ht= -4.9(0)2+ 450= 450 | 1 | ht= -4.9(1)2+ 450= 445.1 | 2 | ht= -4.9(2)2+ 450= 430.4 | 3 | ht= -4.9(3)2+ 450= 405.9 | 4 | ht= -4.9(4)2+ 450=371.6 | 5 | ht= -4.9(5)2+ 450=327.5 | 6 | ht= -4.9(6)2+ 450= 273.6 | 7 | ht= -4.9(7)2+ 450= 209.9 | 8 | ht= -4.9(8)2+ 450= 136.4 | 9 | ht= -4.9(9)2+ 450=53.1 | 10 | ht= -4.9(10)2+ 450= -40 |
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