EXERIMENT.NO. 4 Resolving Forces in Truss STRUCTURAL MECHANICS 1 (CIVIL0006) Submitted by: Fahad Ali AL-Amri 11f8247 Session B Submitted to: Dr. Ram Kishore Manchiryal Fall2014 1. Experiment Name: Resolving Forces in Truss 2. Aim: The force in the member of truss is to be compared with the forces measured in the members with the values found by resolution at the joints. 3. Scope of the experiment: The experiment is to know the nature of force in each member of the
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work on the principles of gravity and air resistance and in effect‚ terminal velocity. Air resistance (air friction) Air resistance is an upward force exerted on a body while it is in the air and is the result of air molecules that come in contact with the surface of the falling object. This force attempts to counteract gravity and other downwards forces influencing a body. The amount of air resistance encountered by an object is dependent on two factors: speed of the object and surface area. Air
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A1 Studying force of friction Objective To investigate the effect on friction of the following factors: 1. normal force that presses the two surfaces together 2. materials that the two surfaces are made of 3. area in contact of the two surfaces Apparatus Rectangular wooden block Wooden plank Glass plate Plastic plate String Scissors Jack Spring balance Electronic balance Half-meter rule Retort stand and clamp G-clamp Trolley[pic]2 Standard weights (100g)[pic]5 Theory
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The Five Competitive Forces Model In this section‚ the structure of our company will be explained using the five competitive forces model developed by Harvard professor Michael Porter. These forces include: rivalry among existing firms‚ threat of new entrants‚ bargaining power of buyers‚ threat of substitutes and bargaining power of suppliers. Each of these forces will have their own distinctive effect on determining industry profitability. Intensity of rivalry among competitors: Recently there
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systems all forces and torques sum to zero. In problems where the first and second conditions of equilibrium are satisfied‚ the best strategy is to create FBD’s for both the first and second conditions‚ derive equations based on these FBD’s and then see what useful information may be gleaned from these equations. When applying the second condition we are free to choose any axis about which to compute torques. It is best to choose an axis that eliminates one or more forces that have lines of force that pass
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Six Forces Porter’s forces analysis is a framework for industry analysis and business strategy development that draws upon industrial organization economics to determine the competitive intensity and overall industry profitability. These forces are 1) potential entry of new competitors‚ 2) bargaining power of suppliers‚ 3) bargaining power of buyers‚ 4) substitute products‚ 5) rivalry among competing sellers in an industry‚ and 6) power of stakeholders. A change in any of the forces normally
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Addition of Force Vectors Abstract The purpose‚ of this experiment‚ was to prove that there is a relation between the magnitude of the resulting vector‚ and the angle between the vectors that are being added. The test was performed by creating a balance between three weights tied to strings on a pulley that transferred the string on top of a graduated disc‚ which made easy the measurement of the angles between them. After performing the experiment‚ my group concluded that there is a relation
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0m. Neglecting friction between the car and road‚ find (a) v and (b) the horizontal force exerted on the car. 25) A daredevil on a motorcycle leaves the end of a ramp with a speed of 35.0 m/s as in the figure P5.25. If his speed is 33.0 m/s when he reaches the peak of the path‚ what is the maximum height that he reaches? Ignore friction and air resistance. 31) A horizontal spring attached to a wall has a force constant of 850 N/m. A block of mass 1.00 kg is attached to the spring and oscillates
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yields two integrations: x = x0+v0t+1/2at2 v = v9+at These two expressions show the relationship between position‚ velocity‚ and acceleration at a given time. Newton’s 2nd law states that the acceleration of an object depends on the net force acting upon the object and the mass of the object. If there were no friction in this experiment‚ then the acceleration of the glider would be equal to acceleration of gravity multiplied by the angle between the air track and the horizontal table (g
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Centripetal force From Wikipedia‚ the free encyclopedia Jump to: navigation‚ search Not to be confused with Centrifugal force. This article contains many unreferenced sections and needs additional citations for verification. Please help improve this article by adding citations to reliable sources. Unsourced material may be challenged and removed. (January 2011) Roller coaster cars are forced through a loop by the track applying a centripetal force on them. A reactive centrifugal force is applied
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