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    Exponential Function

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    Identify the choice that best completes the statement or answers the question. ____ 1. Tell whether the function y = 2( 5 ) shows growth or decay. Then graph the function. a. This is an exponential growth function. c. This is an exponential decay function. x b. This is an exponential growth function. d. This is an exponential growth function. ____ 2. Graph the inverse of the relation. Identify the domain and range of the inverse. x y −1 4 1 2 3 1 5 0 7 1 a. c. Domain: {x | 0 ≤ x ≤ 4}; Range:

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    Exponential function

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    In mathematics‚ the exponential function is the function ex‚ where e is the number (approximately 2.718281828) such that the function ex is its own derivative.[1][2] The exponential function is used to model a relationship in which a constant change in the independent variable gives the same proportional change (i.e. percentage increase or decrease) in the dependent variable. The function is often written as exp(x)‚ especially when it is impractical to write the independent variable as a superscript

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    Exponential Funtions

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    Exponential Functions An exponential function is in which a constant base is raised to a variable power. Exponential functions are used to model changes in population size‚ in the spread of diseases‚ and the growth of investments. They can also accurately predict types of decline typified by radioactive decay. The essence of exponential growth‚ and a characteristic of all exponential growth functions‚ is that they double in size over regular intervals. The most important exponential function is

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    G Exploring Exponential Models 1 x 3. y 5 2 Q 5 R Graph each function. 1. y 5 (0.3)x 6 Date 2. y 5 3x y 6 y y 4 4 2 2 x x Ϫ2 O 2 Ϫ2 O 2 x Ϫ2 O 1 4. y 5 2(3)x 5. s(t) 5 2.5t y 6 s(t) 6 f(x) 4 2 4 6 4 1 6. f (x) 5 2(5)x 2 2 2 Ϫ2 O x t x 2 1 x 7. y 5 0.99 Q 3 R decay; 0.99 Ϫ2 O Ϫ2 O 2 2 Without graphing‚ determine whether the function represents exponential growth or exponential

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    Solving Exponential and Logarithmic Equations Exponential Equations (variable in exponent position) 1. Isolate the exponential portion ( base exp onent ): Move all non-exponential factors or terms to the other side of the equation. 2. Take ln or log of each side of the equation. • Make sure to use ln if the base is “e”. Then remember that ln e = 1 . • Make sure to use log if the base is 10. • If the base is neither “e” nor “10”‚ use either ln or log‚ your choice.. 3. Bring the power (exponent)

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    balancing equations

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    Balancing Equations Balancing equations is a fundamental skill in Chemistry. Solving a system of linear equations is a fundamental skill in Algebra. Remarkably‚ these two field specialties are intrinsically and inherently linked. 2 + O2 ----> H2OA. This is not a difficult task and can easily be accomplished using some basic problem solving skills. In fact‚ what follows is a chemistry text’s explanation of the situation: Taken from: Chemistry Wilberham‚ Staley‚ Simpson‚ Matta Addison Wesley

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    a relation in which each element of the domain is paired with exactly one element in the range. Two types of functions are the exponential functions and the logarithmic functions. Exponential functions are the functions in the form of y = ax‚ where ’’a’’ is a positive real number‚ greater than zero and not equal to one. Logarithmic functions are the inverse of exponential functions‚ y = loga x‚ where ’’a’’ is greater to zero and not equal to one. These functions have certain differences as well as

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    Unix and Equations

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    Upstream: 60 = 6(b-c) Downstream: 60 = 3(b+c) There are now two separate equations: 60 = 6b - 6c and 60 = 3b + 3c Solve both equations for b: b = 10 + c b = 10 - c Now make both equations equal each other and solve for c: 10 + c = 10 - c 2c = 0 c = 0 The speed of the current was 0 mph Now‚ plug the numbers into one of either the original equations to find the speed of the boat in still water. I chose the first equation: b = 10 + c or b = 10 + 0 b = 10 The speed of the boat in still water must

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    05A2009 =0.50(83000) + 0.30(67000) + 0.15(64000) + 0.05(48000) = 41‚500 + 20‚100 + 9‚600 + 2‚400 = $73‚600 $73‚600 is the forecast for 2013 Q2. Using exponential smoothing with a weight of 0.6 on actual values: a) If sales are $45‚000 and $50‚000 for 2010 and 2011‚ what would you forecast for 2012? (The first forecast is equal to the actual value of the preceding year.) Actual values are 2010: $45‚000

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    1 1 Equations And Graphs

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    1.1. Equations and Graphs In each of problems 1 - 4‚ find (a) an ordered pair that is a solution of the equation‚ (b) the intercepts of the graph‚ and (c) determine if the graph has symmetry. 1.   2.   3.   4.   5. Once a car is driven off of the dealership lot‚ it loses a significant amount of its resale value. The graph below shows the depreciated value of a BMW versus that of a Chevy after  years. Which of the following statements is the best conclusion about the data?  a. You should

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