Ben Cosh George Reuter IB Math 20 January 2013 Gold Medal Heights Introduction: a) The Olympic Games is an international event featuring summer and winter sports‚ in which athletes participate in different competitions. Since the Olympic Games began they have been the competition grounds for the world’s greatest athletes. First place obtaining gold; second silver and third bronze. The Olympic medals represent the hardship of what the competitors of the Olympics have done in order
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trading account - A profit and loss account EXAMPLE OF INCOME STATEMENT EXAMPLE OF BALANCED SHEET INTRODUCTION BOOK OF PRIME ENTRY •Book of prime entry is also known as double-entry bookkeeping which is based on the same idea as the accounting equation. •Every accounting transaction has two equal but opposite effects. •Equality of assets and liabilities is preserved. •Therefore‚ in a system of double entry bookkeeping‚ every accounting event must be entered in ledger accounts. •Both as a debit
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Rate of Decomposition of Calcium Carbonate Theory Calcium carbonate‚ CaCO3‚is one of the most abundant minerals on the Earth. More than 4% of the Earth’s crust is composed of calcium carbonate. It is a major component in limestone‚ marble‚ seashells‚ bedrock‚ etc. Limestone and marble have been among the most widely used building materials for more than 5 000 years‚ from the pyramids in Egypt to the Parthenon in Greece and the Taj Mahal in India. In many places‚ limestone is also the foundation
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CARIBBEAN EXAMINATIONS COUNCIL Caribbean Advanced Proficiency Examination Pure Mathematics Syllabus Effective for examinations from May/June 2008 Correspondence related to the syllabus should be addressed to: The Pro-Registrar Caribbean Examinations Council Caenwood Centre 37 Arnold Road‚ Kingston 5‚ Jamaica‚ W.I. Telephone Number: (876) 920-6714 Facsimile Number: (876) 967-4972 E-mail address: cxcwzo@cxc.org Website: www.cxc.org Copyright © 2007‚ by Caribbean Examinations Council The Garrison
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Thus I assumed an asymptote at 23°C. 1st equation: An equation for an exponentially decaying graph is in the form of: y = a + b (e –m x) Where: a= Vertical Translations (Ambient Temperature)‚ b= Dilations‚ m= Gradient x= Time (t)‚ y= Temperature (T (t)) From the data‚ we know that the value of ‘a’ is always equal to 23 °C. The original equation is equal to: T (t) = 23 + b (e –m t) This part of the investigation had some issues. I had formed the equation but was confused on how to solve it. Later
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is ‚ and its purpose is to solve quadratic equations and can only be applied to a quadratic equation that is in the standard form of (ax2+ bx +c = 0).It is important to differentiate between a quadratic formula and a quadratic equation‚ where the quadratic formula is a tool‚ and the quadratic equation is specifically given to you for the purpose of solving it. When solving a quadratic equation‚ you are basically finding the roots of that specific equation. Those roots will tell you where the line
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combusts as: CH4(g) + O2(g) ---> CO2(g) + 2 H2O(g) Net Ionic Equations Net ionic equations are equations that show only the soluble‚ strong electrolytes reacting (these are represented as ions) and omit the spectator ions‚ which go through the reaction unchanged. When you encounter net ionic equations on the test‚ you’ll need to remember the following solubility rules‚ so memorize them! Also keep in mind that net ionic equations‚ which are the bare bones of the chemical reaction‚ usually take
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Oklahoma Algebra II End-of-Instruction Test Preparation and Practice Teacher’s Guide Help for the Oklahoma ACE Algebra II Test i-viii_OK_A2_TE_FM.indd i 7/11/09 12:38:29 AM Copyright © by Houghton Mifflin Harcourt Publishing Company. All rights reserved. No part of this work may be reproduced or transmitted in any form or by any means‚ electronic or mechanical‚ including photocopying or recording‚ or by any information storage or retrieval system‚ without the prior written permission of
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certain run from the previous task was twice duplicated to for a “hot and cold” test for reaction rate. The prior run was again duplicated for a test with catalyst. The data obtained was graphed in a linear regression form‚ using the Arrhenius equation: lnk=-EaR-1T+lnA‚ reaction rate: rate = k[A]x[B]y and other principles held in chemistry. The graph from the results determined that there is a relation between rate and the previously mentioned factors. The results validated the notion that temperature
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the left side of the problem of our equation 25x = 0 or x-12 = 0 this is called the Zero Factor Property we are using X = 0 or x = 12 parabola will cross over the x-axis at 0 and 12. I have solved for x. Now we will find the axis symmetry the x = - b/2a. We determine here if the Parabola has a maximum or a minimum value. At this point we will now solve the equation by breaking down the a = -25‚ b = 300
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