Resultant
236 Computation of the resultant of parallel forces acting on the lever
Problem 236
A parallel force system acts on the lever shown in Fig. P-236. Determine the magnitude and position of the resultant.
Solution 236
downward
clockwise
to the right of A Thus, R = 110 lb downward at 6 ft to the right of A. answer
237 Finding the resultant of parallel forces acting on both sides of the rocker arm
Problem 237
Determine the resultant of the four parallel forces acting on the rocker arm of Fig. P-237.
Solution 237
downward
clockwise
to the right of O Thus, R = 50 lb downward at 4 ft to the right of point O. answer
238 Finding the resultant of trapezoidal loading
Problem 238
The beam AB in Fig. P-238 supports a load which varies an intensity of 220 N/m to 890 N/m. Calculate the magnitude and position of the resultant load.
Solution 238
Thus, R = 3330 N downward at 3.6 m to the left of A. answer
239 Resultant of lift on the wing of an airplane
Problem 239
The 16-ft wing of an airplane is subjected to a lift which varies from zero at the tip to 360 lb per ft at the fuselage according to w = 90x1/2 lb per ft where x is measured from the tip. Compute the resultant and its location from the wing tip. Solution 239
upward
Thus, R = 3840 lb upward at 9.6 ft from the tip of the wing. answer
240 How to locate the centroid of metal plate with circular hole
Problem 240
The shaded area in Fig P-240 represents a steel plate of uniform thickness. A hole of 4-in. diameter has been cut in the plate. Locate the center of gravity the plate. Hint: The weight of the plate is equivalent to the weight of the original plate minus the weight of material cut away. Represent the original plate weight of plate by a downward force acting at the center of
Problem 236
A parallel force system acts on the lever shown in Fig. P-236. Determine the magnitude and position of the resultant.
Solution 236
downward
clockwise
to the right of A Thus, R = 110 lb downward at 6 ft to the right of A. answer
237 Finding the resultant of parallel forces acting on both sides of the rocker arm
Problem 237
Determine the resultant of the four parallel forces acting on the rocker arm of Fig. P-237.
Solution 237
downward
clockwise
to the right of O Thus, R = 50 lb downward at 4 ft to the right of point O. answer
238 Finding the resultant of trapezoidal loading
Problem 238
The beam AB in Fig. P-238 supports a load which varies an intensity of 220 N/m to 890 N/m. Calculate the magnitude and position of the resultant load.
Solution 238
Thus, R = 3330 N downward at 3.6 m to the left of A. answer
239 Resultant of lift on the wing of an airplane
Problem 239
The 16-ft wing of an airplane is subjected to a lift which varies from zero at the tip to 360 lb per ft at the fuselage according to w = 90x1/2 lb per ft where x is measured from the tip. Compute the resultant and its location from the wing tip. Solution 239
upward
Thus, R = 3840 lb upward at 9.6 ft from the tip of the wing. answer
240 How to locate the centroid of metal plate with circular hole
Problem 240
The shaded area in Fig P-240 represents a steel plate of uniform thickness. A hole of 4-in. diameter has been cut in the plate. Locate the center of gravity the plate. Hint: The weight of the plate is equivalent to the weight of the original plate minus the weight of material cut away. Represent the original plate weight of plate by a downward force acting at the center of