why does a kettle boil
PHYS1110 Lab report: “Why does your kettle boil”.
To do this investigation, I agree that I will follow all the risk control methods and conduct the experiment in a very safe condition.
The aim of this investigation is to find out more about boil water by using a kettle. For example, time taken to boil different volumes of water, specific heat of water and power of kettle.
Equipment:
This picture shows all the equipment that I used to do the experiment including a stop watch, a measuring jug and an electric kettle with power between 1850w-2200w.
Table 1: Time taken to boil five different volumes of water
Volume (L)
Time 1 (s)
Time 2 (s)
Time 3 (s)
Average
uncertainty
time (s)
in
the
average time (s)
0.25
57
57.5
58
57.5
0.5
0.5
95
94
96
95
1
0.75
132
135
134
133.7
1
1
169
171
168
169.3
1.5
1.25
209
211
212
210.7
1.5
To keep the data more accurate, I empty and cooling the kettle thoroughly before doing the next boiling.
Diagram 1
Average Time taken to boil water
250
y = 152.28x + 19.03
Time (s)
200
150
100
50
0
0
0.2
0.4
0.6
0.8
1
1.2
1.4
Volume (L)
As shown on the graph, there is a positive relation between time taken to boil water and the volume of water. The equation for this line is y = 152.28x + 19.03. Therefore, the
gradient of this line is 152.28.
As initial and final temperature are set at 25.0o C and 100o C and the power of the kettle is 2025w (middle of the power range 1850w-2200w). Therefore, the heat of water can be calculated by using the equation: gradient =
??∆?
?
Where gradient is 152.28, cw = the heat of water, ΔT= change in temperature, P= power of the kettle. Therefore, cw =
????????×?
ΔT
=
152.28×2025?
100o C−25.0o C
=
308367
75
= 4111.56J/kg °
C,
which means it costs 4111.56J of energy to rise 1kg of water by 1°
C
To do this investigation, I agree that I will follow all the risk control methods and conduct the experiment in a very safe condition.
The aim of this investigation is to find out more about boil water by using a kettle. For example, time taken to boil different volumes of water, specific heat of water and power of kettle.
Equipment:
This picture shows all the equipment that I used to do the experiment including a stop watch, a measuring jug and an electric kettle with power between 1850w-2200w.
Table 1: Time taken to boil five different volumes of water
Volume (L)
Time 1 (s)
Time 2 (s)
Time 3 (s)
Average
uncertainty
time (s)
in
the
average time (s)
0.25
57
57.5
58
57.5
0.5
0.5
95
94
96
95
1
0.75
132
135
134
133.7
1
1
169
171
168
169.3
1.5
1.25
209
211
212
210.7
1.5
To keep the data more accurate, I empty and cooling the kettle thoroughly before doing the next boiling.
Diagram 1
Average Time taken to boil water
250
y = 152.28x + 19.03
Time (s)
200
150
100
50
0
0
0.2
0.4
0.6
0.8
1
1.2
1.4
Volume (L)
As shown on the graph, there is a positive relation between time taken to boil water and the volume of water. The equation for this line is y = 152.28x + 19.03. Therefore, the
gradient of this line is 152.28.
As initial and final temperature are set at 25.0o C and 100o C and the power of the kettle is 2025w (middle of the power range 1850w-2200w). Therefore, the heat of water can be calculated by using the equation: gradient =
??∆?
?
Where gradient is 152.28, cw = the heat of water, ΔT= change in temperature, P= power of the kettle. Therefore, cw =
????????×?
ΔT
=
152.28×2025?
100o C−25.0o C
=
308367
75
= 4111.56J/kg °
C,
which means it costs 4111.56J of energy to rise 1kg of water by 1°
C