Purpose: To determine the amount of work performed and the power developed when climbing a set of stairs and to determine the relationship between power and time.
Pre-Lab Questions:
1. Power is the rate at which work is done. The work divided by the time it takes for the work to be done equals power.
2. The unit for power is the Watt which is Joules/second.
3. One horsepower (hp) is 746 watts.
Procedure:
In this lab, we calculated the work performed and the power that person creates when he or she climbs and runs a set of stairs. Each step in the stair had a vertical distance (height) of 0.166 m. since there was a total of 10 steps; the total vertical distance was 1.66 meters. Since we were only concerned with work in …show more content…
The work done while running and walking the stairs is exactly the same because the work only depends on the weight of the person and the vertical displacement achieved. Since the weight of a person does not change when he or she walks or runs and since the vertical displacement does not change from time to time, the work done is exactly the same. Furthermore, since time is not considered in the equation W=Fd, time is not a factor for work. Therefore, a student whose mass is 89 kg and whose weight is 873N does the same amount of work no matter the speed at which he walks or runs because the vertical displacement(1.66 m) as well as his weight remain constant.
3. Neither the larger nor the smaller students used more power to get up the flight of stairs because mass had no effect on power. The time a person took to reach the top is essential in determining power as the work divided by the time equals power. Student C (mass=74 kg, Weight=725.9 N) created .30 horsepower while Student F (mass=63 kg, Weight=618.03) created .30 horsepower. These two students created the same power output despite their very different masses and weight and thus proving that mass had no effect on the power