Seperation of a mixture of solids
Laboratory 4: Separation of a Mixture of Solids
Numbers 1 to 4 below are not written out in your Lab Manual. They are provided here to help you do your calculations more clearly.
1. Separating out the Iron:
Mass of Weighing Dish: ___0.6_______g
(Read all masses to the decimal places allowed by the balance/scale, typically one or two decimals, i.e. a tenth or a hundredth of a gram.)
Mass of Weighing Dish plus Solids Mixture: ____7.5______ g
Mass of Solids Mixture: ___6.9_______ g
Mass of Weighing Paper: ___0.7______g
Mass of Weighing Paper plus Iron: ____2.6______g
Mass of Iron: ___1.9_______g
2. Separating out the Sand:
Mass of Weighing Dish: __0.7________g
Mass of Weighing Dish plus Sand: ___2.6_______g
Mass of Sand: ___1.9_______g
3. Separating out the Benzoic Acid:
Mass of Paper Cup (to be used in #4 below): __2.5________ g
Mass of Filter Paper: ____1.1______g
Mass of Filter Paper plus Benzoic Acid after complete drying: ___1.9_______g
Mass of Benzoic Acid: _____0.8_____g
4. Separating out the Salt:
Mass of Paper Cup plus Sodium Chloride after complete evaporation of water: ___4.7_______g
Mass of Sodium Chloride
(use Mass of Paper Cup from #3 to calculate): ___2.2_______g
Mass (g)
Percent in Mixture*
Iron filings
1.9 g
1.9/6.8*100= 28%
Sand
1.9 g
1.9/6.8*100= 28%
Table Salt
2.2 g
2.2/6.8*100= 32%
Benzoic Acid
0.8 g
0.8/6.8*100= 12%
*Follow rules of calculations with Significant Figures
Calculate the Percent of each Substance (iron, sand, salt, benzoic acid) in the Mixture by dividing the mass of the substance by the mass of the solid mixture (from #1 above), then multiplying by 100. That is,
% Substance = (Mass of Substance / Mass of Solid Mixture) x 100
Questions:
The questions below are different from the ones in page 108 of your Lab Manual. ANSWER THE QUESTIONS BELOW.
A. Add up the Percents of Mixture of the Iron, Sand, Benzoic
Numbers 1 to 4 below are not written out in your Lab Manual. They are provided here to help you do your calculations more clearly.
1. Separating out the Iron:
Mass of Weighing Dish: ___0.6_______g
(Read all masses to the decimal places allowed by the balance/scale, typically one or two decimals, i.e. a tenth or a hundredth of a gram.)
Mass of Weighing Dish plus Solids Mixture: ____7.5______ g
Mass of Solids Mixture: ___6.9_______ g
Mass of Weighing Paper: ___0.7______g
Mass of Weighing Paper plus Iron: ____2.6______g
Mass of Iron: ___1.9_______g
2. Separating out the Sand:
Mass of Weighing Dish: __0.7________g
Mass of Weighing Dish plus Sand: ___2.6_______g
Mass of Sand: ___1.9_______g
3. Separating out the Benzoic Acid:
Mass of Paper Cup (to be used in #4 below): __2.5________ g
Mass of Filter Paper: ____1.1______g
Mass of Filter Paper plus Benzoic Acid after complete drying: ___1.9_______g
Mass of Benzoic Acid: _____0.8_____g
4. Separating out the Salt:
Mass of Paper Cup plus Sodium Chloride after complete evaporation of water: ___4.7_______g
Mass of Sodium Chloride
(use Mass of Paper Cup from #3 to calculate): ___2.2_______g
Mass (g)
Percent in Mixture*
Iron filings
1.9 g
1.9/6.8*100= 28%
Sand
1.9 g
1.9/6.8*100= 28%
Table Salt
2.2 g
2.2/6.8*100= 32%
Benzoic Acid
0.8 g
0.8/6.8*100= 12%
*Follow rules of calculations with Significant Figures
Calculate the Percent of each Substance (iron, sand, salt, benzoic acid) in the Mixture by dividing the mass of the substance by the mass of the solid mixture (from #1 above), then multiplying by 100. That is,
% Substance = (Mass of Substance / Mass of Solid Mixture) x 100
Questions:
The questions below are different from the ones in page 108 of your Lab Manual. ANSWER THE QUESTIONS BELOW.
A. Add up the Percents of Mixture of the Iron, Sand, Benzoic