By adding AgNO3, a white precipitate was formed. According to data from week one NaCl had to be present because the other anions would have created a precipitate in a different color. After centrifuging and separating the sample we added BaCl2 which resulted in another white precipitate. The reaction showed that Na2SO4 must have been present and not Na2CO3 because there was no brown precipitate formed in the previous reaction and Na2SO4 would have been the only anion to create a white precipitate with BaCl2. After adding both reagents it was clear that unknown sample 1 contained NaCl and
By adding AgNO3, a white precipitate was formed. According to data from week one NaCl had to be present because the other anions would have created a precipitate in a different color. After centrifuging and separating the sample we added BaCl2 which resulted in another white precipitate. The reaction showed that Na2SO4 must have been present and not Na2CO3 because there was no brown precipitate formed in the previous reaction and Na2SO4 would have been the only anion to create a white precipitate with BaCl2. After adding both reagents it was clear that unknown sample 1 contained NaCl and