Math 133 Unit 2 Ip
Student Answer form Unit 2
1.
a. x-4x=-6
A) 1 B) -10 C) -6 X^2-10x-24=0 (X-4) (x+6) X-4=0 x=4 X+6=0 x+-6
b. x=7+4=5.5 x=7-4=1.5
x=-b±b2-4ac2a x= (-7) ± (-7)2-4(3) (20)2a x=7±64-802a x=7±-16 x=7+4/2=5.5 x=7-4/2=1.5
c. 10x^2+x-3=0
x=-b±b2-4ac2a x=-1± (1)2-4(10) (-3)2(10) x=1±1-12020 x=1±10 x=1+320 = 5 x=1-320= 10
2.
a. (-2.3, 0), (0, 6.3)
b. This is a maximum function.
This is a maximum function because it is at the peak of the parabola.
c. (2, 9)
d. x=2
3.
a. s= -16t^2+64t+25
b. 73 Feet
S= -16◦(1)^2+64◦(1)+25 S= -16+64+25 S=73 feet
c. 2 seconds
-b2a= -642(-16)= -64/-32=2 seconds
d. 89 feet
S= -16*(2)^2+64*(2)+25 S= 64+128+25= 89 feet
4.
a. x | y | -2 | 4 | -1 | 0 | 0 | -2 | 1 | -2 | 2 | 0 | 3 | 4 |
Y=x^2-x-2
X=-2 x= -1 x=0 x=1 Y=-2^2-(-2)-2 y= -1^2-(-1)-2 y= 0^2-0-2 y=1^2-1-2 Y=4+2-2 y= 1+1 -2 y= -2 y= 1-1-2 Y=6-2 y= 2-2 y= 0-2 Y=4 y=0 y= -2
X=2 x=3 Y=2^2-2-2 y=3^2-3-2 Y=4-2-2 y=9-3-2 Y=2-2
b. [pic]
c. x intercept is (2,0) y intercept is
1.
a. x-4x=-6
A) 1 B) -10 C) -6 X^2-10x-24=0 (X-4) (x+6) X-4=0 x=4 X+6=0 x+-6
b. x=7+4=5.5 x=7-4=1.5
x=-b±b2-4ac2a x= (-7) ± (-7)2-4(3) (20)2a x=7±64-802a x=7±-16 x=7+4/2=5.5 x=7-4/2=1.5
c. 10x^2+x-3=0
x=-b±b2-4ac2a x=-1± (1)2-4(10) (-3)2(10) x=1±1-12020 x=1±10 x=1+320 = 5 x=1-320= 10
2.
a. (-2.3, 0), (0, 6.3)
b. This is a maximum function.
This is a maximum function because it is at the peak of the parabola.
c. (2, 9)
d. x=2
3.
a. s= -16t^2+64t+25
b. 73 Feet
S= -16◦(1)^2+64◦(1)+25 S= -16+64+25 S=73 feet
c. 2 seconds
-b2a= -642(-16)= -64/-32=2 seconds
d. 89 feet
S= -16*(2)^2+64*(2)+25 S= 64+128+25= 89 feet
4.
a. x | y | -2 | 4 | -1 | 0 | 0 | -2 | 1 | -2 | 2 | 0 | 3 | 4 |
Y=x^2-x-2
X=-2 x= -1 x=0 x=1 Y=-2^2-(-2)-2 y= -1^2-(-1)-2 y= 0^2-0-2 y=1^2-1-2 Y=4+2-2 y= 1+1 -2 y= -2 y= 1-1-2 Y=6-2 y= 2-2 y= 0-2 Y=4 y=0 y= -2
X=2 x=3 Y=2^2-2-2 y=3^2-3-2 Y=4-2-2 y=9-3-2 Y=2-2
b. [pic]
c. x intercept is (2,0) y intercept is