Magnesium Oxide Lab
The Law of Definite Proportions states that a chemical compound contains the same element in exactly the same proportions by mass regardless of the size of the sample or source of the compound. This relates to the magnesium oxide lab because we tested out this theory to see if it is true that the law of definite proportions says that a chemical compound contains the same element in exactly the same proportions by mass regardless of the size of the sample or source of the compound. In this experiment, you first find the mass of the crucible and cover. Next, you will find the mass of crucible, cover and Mg. After that, you will crumple up the Mg and put it into the crucible and put the cover on over the bunsen burner with heating it for four min. Then you will remove the lid slightly and let it heat for another
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Then our quantitative data for the mass of crucible and cover is 32.24g. The mass of the crucible, cover, and Mg is 32.54g and the mass of crucible cover and the product is 34.86g. Once my group found out all of those measurements, we could find the mass of the magnesium that reacted. That equation is the mass of the Mg, crucible and cover - mass of crucible and cover and that would be 32.54 - 32.24= 0.30g. After that, we found the mass of the magnesium oxide that was produced. The equation for the mass of magnesium oxide that was produced is a mass of product, crucible and cover - a mass of crucible and cover = mass of product. 34.86- 32.24= 2.64 After that we found the mass of oxygen reacted. The equation is a mass of product - mass of Mg = oxygen reacted. 2.62-0.30=1.23g of oxygen. next we found the ratio of the mass of magnesium to the mass of oxygen it would be a Mass of Mg/Mass of oxygen= a decimal 2.62/2.32=1.23g And that would lead us to find the % error. and our % error is
Then our quantitative data for the mass of crucible and cover is 32.24g. The mass of the crucible, cover, and Mg is 32.54g and the mass of crucible cover and the product is 34.86g. Once my group found out all of those measurements, we could find the mass of the magnesium that reacted. That equation is the mass of the Mg, crucible and cover - mass of crucible and cover and that would be 32.54 - 32.24= 0.30g. After that, we found the mass of the magnesium oxide that was produced. The equation for the mass of magnesium oxide that was produced is a mass of product, crucible and cover - a mass of crucible and cover = mass of product. 34.86- 32.24= 2.64 After that we found the mass of oxygen reacted. The equation is a mass of product - mass of Mg = oxygen reacted. 2.62-0.30=1.23g of oxygen. next we found the ratio of the mass of magnesium to the mass of oxygen it would be a Mass of Mg/Mass of oxygen= a decimal 2.62/2.32=1.23g And that would lead us to find the % error. and our % error is