Lind Chapter 3: Exercise 60
Lind Chapter 3: Exercise 60
Owens Orchards sells apples in a large bag by weight. A sample of seven bags contained the following numbers of apples: 23,19,26,17,21,24,22.
a. Compute the mean number and median number of apples in a bag. Total number of Problems = 11
Mean = (23+19+26+17+21+24+22)/7 = 21.71 Problems correct = 8
Median = 22 CORRECT
List of # in order from low to high: 17,19,21,22,23,24,26
List of # in order from high to low: 26,24,23,22,21,19,17 b. Verify that Σ(x-xbar) = 0.
(17-21.71)+(19-21.71)+(21-21.71)+(22-21.71)+(23-21.71)+(24-21.71)+(26-21.71) ≈ 0 Lind Charpter 3: Exercise 62 …show more content…
What is the probability that a particular driver had exactly two speeding violations?
Probability of event happening (PE)= #of favorable outcomes/total # of possible outcomes
PE = 18/2000 d. What concept of probability does this illustrate?
EMPIRICAL
Lind Chapter 5: Exercise 66
A survey of undergraduate students in the School of Business at Northern University revealed the following regarding the gender and majors of the students:
Column1 Column2 Column3 Column4 Column5
Gender Accounting Management Finance Total
Male 100 150 50 300
Female 100 50 50 200
Total 200 200 100 500 a. What is the probability of selecting a female student?
Probability of selecting a female student (PE) = # of female student / total # of student
PE = 200/500
PE = 0.4 b. What is the probability of selecting a finance or accounting major?
P(fiance major) = A = 100/500
P(accounting major) = B = 200/500
P(AorB) = P(A) + P(B)
P(AorB) = 100/500 +
Owens Orchards sells apples in a large bag by weight. A sample of seven bags contained the following numbers of apples: 23,19,26,17,21,24,22.
a. Compute the mean number and median number of apples in a bag. Total number of Problems = 11
Mean = (23+19+26+17+21+24+22)/7 = 21.71 Problems correct = 8
Median = 22 CORRECT
List of # in order from low to high: 17,19,21,22,23,24,26
List of # in order from high to low: 26,24,23,22,21,19,17 b. Verify that Σ(x-xbar) = 0.
(17-21.71)+(19-21.71)+(21-21.71)+(22-21.71)+(23-21.71)+(24-21.71)+(26-21.71) ≈ 0 Lind Charpter 3: Exercise 62 …show more content…
What is the probability that a particular driver had exactly two speeding violations?
Probability of event happening (PE)= #of favorable outcomes/total # of possible outcomes
PE = 18/2000 d. What concept of probability does this illustrate?
EMPIRICAL
Lind Chapter 5: Exercise 66
A survey of undergraduate students in the School of Business at Northern University revealed the following regarding the gender and majors of the students:
Column1 Column2 Column3 Column4 Column5
Gender Accounting Management Finance Total
Male 100 150 50 300
Female 100 50 50 200
Total 200 200 100 500 a. What is the probability of selecting a female student?
Probability of selecting a female student (PE) = # of female student / total # of student
PE = 200/500
PE = 0.4 b. What is the probability of selecting a finance or accounting major?
P(fiance major) = A = 100/500
P(accounting major) = B = 200/500
P(AorB) = P(A) + P(B)
P(AorB) = 100/500 +