Ib Chemistry Analysis of Iron Tablets
DCP + CE: An Analysis of Iron Tablets
|Pipette Solution |Iron (II) solution | |25 cm3 |
|Burette Solution |Potassium Manganate (VII) |0.01 moldm-3 | |
| |Trial |1 |2 |3 | |
|Burette Readings |Final |11.35 |10.90 |10.95 |10.95 | |
| |Initial |0.00 |0.00 |0.00 |0.00 | |
|Volume Used (Titre)/ cm3 |11.35 |10.90 |10.95 |10.95 | |
|Mean Titre/ cm3 |10.95 | | |
|Qualitative Data |Colour change- |Colour change- |Colour change- |Colour change- | |
| |purple to pink |purple to pale |purple to pale |purple to pale pink| |
| |(overshoot) |pink |pink | | |
Raw Data Table:
Titration of iron (II) solution with 0.01M potassium manganate (VII) solution
Chemical reaction during titration:
5Fe2+ ( 5Fe3+ + 5e- oxidation
+) MnO4- + 8H+ + 5e- ( Mn2+ + 4H2O reduction 5Fe2+ + MnO4- + 8H+ ( 5Fe3+ +Mn2+ + 4H2O
Mass of Iron used (weigh by difference)
Mass of container + iron tablets = 14.57g
Mass of container = 13.05g
Mass of iron used = 1.52g
No of moles of MnO4- in solution n(MnO4-) = concentration * volume used (titre) = 0.01moldm3 * 10.95 cm3/ 1000 = 1.095 * 10-4 mol
No of
|Pipette Solution |Iron (II) solution | |25 cm3 |
|Burette Solution |Potassium Manganate (VII) |0.01 moldm-3 | |
| |Trial |1 |2 |3 | |
|Burette Readings |Final |11.35 |10.90 |10.95 |10.95 | |
| |Initial |0.00 |0.00 |0.00 |0.00 | |
|Volume Used (Titre)/ cm3 |11.35 |10.90 |10.95 |10.95 | |
|Mean Titre/ cm3 |10.95 | | |
|Qualitative Data |Colour change- |Colour change- |Colour change- |Colour change- | |
| |purple to pink |purple to pale |purple to pale |purple to pale pink| |
| |(overshoot) |pink |pink | | |
Raw Data Table:
Titration of iron (II) solution with 0.01M potassium manganate (VII) solution
Chemical reaction during titration:
5Fe2+ ( 5Fe3+ + 5e- oxidation
+) MnO4- + 8H+ + 5e- ( Mn2+ + 4H2O reduction 5Fe2+ + MnO4- + 8H+ ( 5Fe3+ +Mn2+ + 4H2O
Mass of Iron used (weigh by difference)
Mass of container + iron tablets = 14.57g
Mass of container = 13.05g
Mass of iron used = 1.52g
No of moles of MnO4- in solution n(MnO4-) = concentration * volume used (titre) = 0.01moldm3 * 10.95 cm3/ 1000 = 1.095 * 10-4 mol
No of