Hgd Handbook Answers
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Analytical Chemistry
CHEM 2354
Analytical Chemistry
CHM 2354, Winter 2015
Schedule:
Monday LAB
14:30-18:30
Marion Hall (MRN)
Room: 301
Tuesday DGD
Thursday DGD
Thursday LEC
Tuesday LEC
14:30-15:30
14:30-15:30
08:30-10:00
10:00-11:30
HGN
FSS
Montpetit Hall (MNT)
Montpetit Hall (MNT)
Room: 302
Room: 2005
Room: 202
Room: 202
Instructor: Professor Maxim Berezovski
Office:
Address: D’Iorio Hall room 201
Phone: 613-562-5800 ext. 1898 e-mail: Maxim.Berezovski@uottawa.ca web page: http://mysite.science.uottawa.ca/mberezov/
Office Hours:
15:30-17:30 Tuesdays & Thursdays (after DGDs) or by Special Appointment
I am in my office many other times during the week and am always willing to speak with you if you find me in or make an appointment. …show more content…
- Concentrations of gases should be expressed in bars. express gas as Pgas, emphasize pressure instead of concentration
► 1 bar = 105 Pa; 1 atm = 1.01325 bar
►
- Concentrations of pure solids, pure liquids and solvents are omitted
► are unity
► standard
state is the pure liquid or solid
3.) Manipulating Equilibrium Constants
Consider the following reaction:
[ H ][ A ]
K1
[ HA]
Reversing the reaction results in a reciprocal equilibrium reaction:
K '1
[ HA]
[ H ][ A ]
1 / K 1
Chemical Equilibrium
Equilibrium Constant
3.) Manipulating Equilibrium Constants
If two reactions are added, the new K is the product of the two individual K values:
K1
K2
K3
[ H ][ A ]
K1
[ HA]
K2
[CH ]
[ H ][C ]
[ A ][CH ]
K3
[ HA][C ]
[ H ][ A ] [CH ] [ A ][CH ]
K 3 K1K 2
[ HA]
[ HA][C ]
[ H ][C ]
Chemical Equilibrium
Equilibrium Constant
3.) Manipulating Equilibrium Constants
Example:
Given the reactions and equilibrium constants:
Kw= 1.0 x 10-14
KNH3= 1.8 x 10-5
Find the equilibrium constant for the reaction:
Solution:
K1=
Analytical Chemistry
CHEM 2354
Analytical Chemistry
CHM 2354, Winter 2015
Schedule:
Monday LAB
14:30-18:30
Marion Hall (MRN)
Room: 301
Tuesday DGD
Thursday DGD
Thursday LEC
Tuesday LEC
14:30-15:30
14:30-15:30
08:30-10:00
10:00-11:30
HGN
FSS
Montpetit Hall (MNT)
Montpetit Hall (MNT)
Room: 302
Room: 2005
Room: 202
Room: 202
Instructor: Professor Maxim Berezovski
Office:
Address: D’Iorio Hall room 201
Phone: 613-562-5800 ext. 1898 e-mail: Maxim.Berezovski@uottawa.ca web page: http://mysite.science.uottawa.ca/mberezov/
Office Hours:
15:30-17:30 Tuesdays & Thursdays (after DGDs) or by Special Appointment
I am in my office many other times during the week and am always willing to speak with you if you find me in or make an appointment. …show more content…
- Concentrations of gases should be expressed in bars. express gas as Pgas, emphasize pressure instead of concentration
► 1 bar = 105 Pa; 1 atm = 1.01325 bar
►
- Concentrations of pure solids, pure liquids and solvents are omitted
► are unity
► standard
state is the pure liquid or solid
3.) Manipulating Equilibrium Constants
Consider the following reaction:
[ H ][ A ]
K1
[ HA]
Reversing the reaction results in a reciprocal equilibrium reaction:
K '1
[ HA]
[ H ][ A ]
1 / K 1
Chemical Equilibrium
Equilibrium Constant
3.) Manipulating Equilibrium Constants
If two reactions are added, the new K is the product of the two individual K values:
K1
K2
K3
[ H ][ A ]
K1
[ HA]
K2
[CH ]
[ H ][C ]
[ A ][CH ]
K3
[ HA][C ]
[ H ][ A ] [CH ] [ A ][CH ]
K 3 K1K 2
[ HA]
[ HA][C ]
[ H ][C ]
Chemical Equilibrium
Equilibrium Constant
3.) Manipulating Equilibrium Constants
Example:
Given the reactions and equilibrium constants:
Kw= 1.0 x 10-14
KNH3= 1.8 x 10-5
Find the equilibrium constant for the reaction:
Solution:
K1=