Preview

Crank Mechanism

Powerful Essays
Open Document
Open Document
984 Words
Grammar
Grammar
Plagiarism
Plagiarism
Writing
Writing
Score
Score
Crank Mechanism
Name: Monish Kumar (S11065194)

The University of the South Pacific
MM313 Dynamic Systems
Experiment 2- Crank Mechanism

Aim:
To investigate the relationship between piston displacement and crank angle for different ratios between the connecting rod and the crank. Also to look at the relationship between the turning moment on the crank shaft and crank angle for a given force on the piston.

Equipment and Instrument:

Introduction:
A crank is an arm attached at right angles to a rotating shaft by which reciprocating motion is imparted to or received from the shaft. It is used to convert circular motion into reciprocating motion, or vice-versa. The arm may be a bent portion of the shaft, or a separate arm attached to it. Attached to the end of the crank by a pivot is a rod, usually called a connecting rod. The end of the rod attached to the crank moves in a circular motion, while the other end is usually constrained to move in a linear sliding motion.

Theory:

Figure 1.0: Slider crank mechanism

The slider crank mechanism as shown in figure 1.0 is a kinematic mechanism. The piston displacement from the top dead centre, x, can be determined from the geometry of the mechanism, in terms of the lengths of the connecting rod, L, and crank, R, and the crank angle, θ, can be expressed as x=L+R-(Lcosφ-Rcosϑ) Also from the geometry, it can be seen that

Rsinϑ=Lsinφ
And
sinφ=sinϑn
Hence
cosφ=[1+sinϑn2]1/2
Where n is a ratio: n=LR Procedure:

Part A: 1) No weights and hangers required, the unit initial starting position 0 in the protractor is setup and 90⁰ and 270⁰ protractor positions to be in line with the level lines in each side. 2) The unit is to be setup in its highest point, Top dead centre point was used to work out the displacement value 3) The mounted disc was turned 30⁰ and the displacement was noted on the results table, this step was again repeated for different angles and different crank positions.
Part B:

You May Also Find These Documents Helpful

  • Powerful Essays

    Reciprocating Engine

    • 12659 Words
    • 51 Pages

    a piston as the slider moving inside a fixed cylinder, the mechanism provides the vital…

    • 12659 Words
    • 51 Pages
    Powerful Essays
  • Good Essays

    In this activity you will learn about gear ratios and how they affect speed and torque within a system. You will also construct simple and compound gear systems.…

    • 1427 Words
    • 6 Pages
    Good Essays
  • Good Essays

    Nt1210 Lab 3.1.3

    • 427 Words
    • 2 Pages

    Where H_2 is the horsepower transmitted between shafts, Ks is the strand correction factor, Kr is the roller correction factor, N_1 is the number of teeth of the driving sprocket, n_1 is the rpm of the driving sprocket, p is the pitch of the chain, Lp is the length of the chain in pitches, and h is the life in hours of the…

    • 427 Words
    • 2 Pages
    Good Essays
  • Good Essays

    Abc Manufacturing Company

    • 827 Words
    • 4 Pages

    Early in 2010 the Tractor division, in conjunction with the Machining division, designed a crankshaft for one of its tractors. The Machining division’s staff spent several months helping to perfect the design, production methods, and materials to be used in the crankshaft. According to an agreement between the two divisions, the Machining division was reimbursed by the Tractor division for the cost of its design and development work.…

    • 827 Words
    • 4 Pages
    Good Essays
  • Good Essays

    Worm Gears Formulas

    • 3385 Words
    • 14 Pages

    Right Angle Gearbox Spiral Bevel, Helical Bevel, Worm for PT & Motion Control, 1-50 HP www.diequa.com…

    • 3385 Words
    • 14 Pages
    Good Essays
  • Good Essays

    The slotted link mechanism is a mechanism able to transform circular movement into reciprocating movement. It consists of a rotary element (graduated disk), called crank, connected to a rigid bar, called a connecting rod. When rotating the crank, the connecting rod moves back and forward. The rotation motion of a crank or crankshaft causes a rectilinear reciprocating motion of a piston or plunger.…

    • 531 Words
    • 3 Pages
    Good Essays
  • Good Essays

    Solution of Control chart

    • 264 Words
    • 13 Pages

    1. Following data are diameters (in mm) of a type of shaft manufactured by a new machine are obtained from an engineering workshop.…

    • 264 Words
    • 13 Pages
    Good Essays
  • Powerful Essays

    Projectile

    • 1347 Words
    • 6 Pages

    7)The previous process was repeated ,each for the displacement of the spherical ball at 10,20,30,40,50,60,70,80,90 degrees…

    • 1347 Words
    • 6 Pages
    Powerful Essays
  • Satisfactory Essays

    Physics Mark Scheme

    • 975 Words
    • 4 Pages

    (a) (i) all positions (accept 20, 40, 60, 80) marked to within ±5° positions are 40°, 70°, 90° and 102° (-1 for each error or omission) (ii) allow 107° → 113° (b) e.g. more sensitive at low volumes (do not allow reference to ‘accuracy’)…

    • 975 Words
    • 4 Pages
    Satisfactory Essays
  • Satisfactory Essays

    Mechanics of Machine

    • 431 Words
    • 2 Pages

    MEEM 3700 – Suggested problems from Chapter 1 1.7.1 Given that ω=5 rad/sec, then the frequency in Hz is f=ω/2π and the period T= 1/f 1.15 The displacement amplitude X=0.15mm or 0.00015m The acceleration amplitude is ω2X = 0.6g = 0.6 (9.81) m/sec2 ω2 = ω2X/ X ; but ω is in rad/sec. Convert rad/sec to rpm to get the shaft speed (1890 rpm). 1.18 p=polyfit(x,f,1) ; p=35.18, -0.0607 and f=35.18x - 0.0607; k=35.18 (the slope of the line) 1.19 For springs end to end (series), 1/keq = 1/k1 = 1/k2 ; for equal springs, the equivalent spring constant is 1/keq = 1/k + 1/k = 2/k and ker = k/2 (weaker) For springs side-by-side (parallel ) keq = k1 + k2 and keq = 2k (twice as stiff) 1.20 1.21 Assume “thickness” is the beam height h. K = f/x, for the doubly clamped beam (both ends clamped), k = f/x = 192EI/L3 and I = 1/12 bh3 Take moments around the pivot point O. The force in each spring is the product of its spring constant (k) and its deflection. fL = (kx)L + (K x/2)L/2 = KLx(5/4) The equivalent spring constant is Keq= f/x = 5K/4…

    • 431 Words
    • 2 Pages
    Satisfactory Essays
  • Good Essays

    Vertical Axis — Leveling the Instrument Vertical Collimation Line of Sight Perpendicular to Trunnion — Double Deflection Check Trunnion Axis Level — Steeple Check…

    • 1216 Words
    • 5 Pages
    Good Essays
  • Better Essays

    • Different throttle valve angles in relation to the accelerator pedal position are used to achieve different engine output characteristics.…

    • 2404 Words
    • 10 Pages
    Better Essays
  • Good Essays

    Land Surveying

    • 941 Words
    • 4 Pages

    3. Determination of the distance reduced to the horizontal do and the level difference between the known…

    • 941 Words
    • 4 Pages
    Good Essays
  • Satisfactory Essays

    The aim of this experiment is to examine the automatic gearbox and determine the gear ratios for each gear (1st, 2nd, 3rd, 4th and reverse)…

    • 413 Words
    • 2 Pages
    Satisfactory Essays
  • Powerful Essays

    The simulation will be done for two different gear ratios, one of which represents low-speed/high-torque…

    • 1566 Words
    • 8 Pages
    Powerful Essays

Related Topics