Chem Thoughtlab
Chemistry 12 Thought lab
Part 1 (Procedure)
1) 1s22s22p23s23p24s23d24p25s24d25p26s24f25d26p2
2) When ml can only equal 1, each energy level can have only 1 orientation so according to the exclusion principle only 2 electrons with opposite spins can be in each orbital. So in order to get to element 30 you would need to go all the way to the 6p orbitals. In other words, every two electrons would necessitate going to a new orbital. 1 | 1s1 | 11 | 1s2 2s2 2p2 3s2 3p2 4s1 | 21 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 4d2 5p1 | 2 | 1s2 | 12 | 1s2 2s2 2p2 3s2 3p2 4s2 | 22 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 4d2 5p2 | 3 | 1s2 2s1 | 13 | 1s2 2s2 2p2 3s2 3p2 4s2 3d1 | 23 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 4d2 5p2 6s1 | 4 | 1s2 2s2 | 14 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 | 24 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 4d2 5p2 6s2 | 5 | 1s2 2s2 2p1 | 15 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p1 | 25 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 4d2 5p2 6s2 4f1 | 6 | 1s2 2s2 2p2 | 16 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 | 26 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 4d2 5p2 6s2 4f2 | 7 | 1s2 2s2 2p2 3s1 | 17 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s1 | 27 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 4d2 5p2 6s2 4f2 5d1 | 8 | 1s2 2s2 2p2 3s2 | 18 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 | 28 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 4d2 5p2 6s2 4f2 5d2 | 9 | 1s2 2s2 2p2 3s2 3p1 | 19 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 4d1 | 29 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 4d2 5p2 6s2 4f2 5d26p1 | 10 | 1s2 2s2 2p2 3s2 3p2 | 20 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 4d2 | 30 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 4d2 5p2 6s2 4f2 5d26p2 |
Part 1 (analysis)
1) In this different universe there is only one orbital of each given type because we are told that ml =1, this means that each orbital can have only one orientation in space, so instead of 3 p orbitals, able to hold a total of 6 electrons, you have only one orbital able to hold 2 electrons.
2) For elements 13 and 14, the principle quantum number (n) would
Part 1 (Procedure)
1) 1s22s22p23s23p24s23d24p25s24d25p26s24f25d26p2
2) When ml can only equal 1, each energy level can have only 1 orientation so according to the exclusion principle only 2 electrons with opposite spins can be in each orbital. So in order to get to element 30 you would need to go all the way to the 6p orbitals. In other words, every two electrons would necessitate going to a new orbital. 1 | 1s1 | 11 | 1s2 2s2 2p2 3s2 3p2 4s1 | 21 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 4d2 5p1 | 2 | 1s2 | 12 | 1s2 2s2 2p2 3s2 3p2 4s2 | 22 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 4d2 5p2 | 3 | 1s2 2s1 | 13 | 1s2 2s2 2p2 3s2 3p2 4s2 3d1 | 23 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 4d2 5p2 6s1 | 4 | 1s2 2s2 | 14 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 | 24 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 4d2 5p2 6s2 | 5 | 1s2 2s2 2p1 | 15 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p1 | 25 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 4d2 5p2 6s2 4f1 | 6 | 1s2 2s2 2p2 | 16 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 | 26 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 4d2 5p2 6s2 4f2 | 7 | 1s2 2s2 2p2 3s1 | 17 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s1 | 27 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 4d2 5p2 6s2 4f2 5d1 | 8 | 1s2 2s2 2p2 3s2 | 18 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 | 28 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 4d2 5p2 6s2 4f2 5d2 | 9 | 1s2 2s2 2p2 3s2 3p1 | 19 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 4d1 | 29 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 4d2 5p2 6s2 4f2 5d26p1 | 10 | 1s2 2s2 2p2 3s2 3p2 | 20 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 4d2 | 30 | 1s2 2s2 2p2 3s2 3p2 4s2 3d2 4p2 5s2 4d2 5p2 6s2 4f2 5d26p2 |
Part 1 (analysis)
1) In this different universe there is only one orbital of each given type because we are told that ml =1, this means that each orbital can have only one orientation in space, so instead of 3 p orbitals, able to hold a total of 6 electrons, you have only one orbital able to hold 2 electrons.
2) For elements 13 and 14, the principle quantum number (n) would