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Causes of Health Problem
1449/1 Mathematics Paper 1 Oct./ ov. 2011 1 ¼ hours

JABATA PELAJARA MELAKA

PEPERIKSAA SELARAS AKHIR TAHU TI GKATA 4, 2011

MATHEMATICS
Paper 1 One hour and fifteen minutes

DO OT OPE THIS QUESTIO PAPER U TIL YOU ARE TOLD TO DO SO 1. This question paper consists of 40 questions. 2. Answer all questions. 3. Answer each question by blackening the correct space on the answer sheet. 4. Blacken only one space for each question. 5. If you wish to change your answer, erase the blackened mark that you have done. Then blacken the space for the new answer . 6. The diagrams in the questions provided are not drawn to scale unless stated. 7. A list of formulae is provided on pages 2 and 3. 8. You may use a non-programmable scientific calculator.

This question paper consists of 28 printed pages

SULIT

2 MATHEMATICAL FORMULAE

1449/1

The following formulae may be helpful in answering the questions. The symbols given are the ones commonly used. RELATIO S 1 2 3 4 a m × a n = a m+ n a m ÷ a n = a m−n

(a m ) n = a mn
A −1 =

1  d − b   ad − bc  − c a    n( A) n (S )

5 6
7

P ( A) =

P ( A' ) = 1 − P( A)
Distance = ( x 2 − x1 ) 2 + ( y 2 − y1 ) 2

8

 x1 + x 2 y1 + y 2  ,  Midpoint , ( x, y ) =  2   2
Average speed =

9

distance travelled time taken

10

Mean = Mean =

sum of data number of data

11 12

sum of(class mark × frequency) sum of frequencie s

Pythagoras Theorem c2 = a2 + b2

13

m=

y 2 − y1 x 2 − x1

14

m=−

y − int ercept x − int ercept

1449/1© 2011 Hak Cipta JPM

[Lihat sebelah SULIT

SULIT

3

1449/1

SHAPES A D SPACE

1 2 3 4 5 6 7 8

Area of trapezium =

1 × sum of parallel sides × height 2

Circumference of circle = πd = 2πr
2 Area of circle = πr

Curved surface area of cylinder = 2πrh
2 Surface area of sphere = 4πr

Volume of right prism = cross sectional area × length Volume of cylinder = πr 2h Volume of cone = 1 2 πr h 3 4 3 πr 3 1 × base area ×

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